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uranmaximum [27]
4 years ago
9

If ABC=85,CBD=140 , and ,ABD=1/2x=30 find the value of x.

Mathematics
2 answers:
damaskus [11]4 years ago
8 0

If ABC=85,CBD=140 , and ,ABD=1/2x=30 find the value of x.

m∠ABD = m∠ABC + m∠CBD

m∠ABC = m∠ABD - m∠CBD

m∠ABC = 85° - m∠CBD

nexus9112 [7]4 years ago
5 0
Based on the given nomenclature of angles, I think the illustration would look like that shown in the attached picture. The common vertex is point B, that's why the middle point of the given angles is B. Now, according to Angle Addition Postulate, the individual interior angles should sum up to the total angle. So, the equation would be

m∠ABD = m∠ABC + m∠CBD
m∠ABC = m∠ABD - m∠CBD
m∠ABC = 85° - m∠CBD

Read more on Brainly.com - brainly.com/question/5023714#readmore
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3 years ago
F(x)=e*1/x<br>Calculate f'(x) ​
Murljashka [212]

Answer:

\huge\boxed{f'(x)=-\dfrac{e^\frac{1}{x}}{x^2}}

Step-by-step explanation:

(e^x)'=e^x\\\\\bigg[f\bigg(g(x)\bigg)\bigg]'=f'\bigg(g(x)\bigg)\cdot g'(x)\\\\\left(\dfrac{1}{x}\right)'=-\dfrac{1}{x^2}\\\\====================

f(x)=e^\frac{1}{x}=\left(e^\frac{1}{x}\right)'\cdot\left(\dfrac{1}{x}\right)'=e^\frac{1}{x}\cdot\left(-\dfrac{1}{x^2}\right)=-\dfrac{e^\frac{1}{x}}{x^2}

6 0
4 years ago
If ∠3 and ∠4 are complementary angles, m∠3 = (x+24)°, and m∠4 = x°, then find the measures of ∠3 and ∠4.
kobusy [5.1K]

Answer:

\huge\boxed{3 = 57 \textdegree}

\huge\boxed{4 = 33 \textdegree}

Step-by-step explanation:

When two angles are complementary, their angle lengths add up to 90°.

Therefore, we can make the equation

(x+24) + (x) = 90

Now we can solve for x.

  • 2x+24=90
  • 2x=66
  • x = 33

Since the measure of ∠4 is just x°, and we know x is 33, that means ∠4 is 33°.

We also have the expression for ∠3, x+24. Since we know x is 33, we can substitute it into the expression.

33+24\\\\57

Hope this helped!

3 0
3 years ago
+
Misha Larkins [42]

Answer: 2x^{2} + 5x -3

Step-by-step explanation:

Find the quotient of  \frac{16x^4+40x^3-24x^2}{8x^2}

Step 1: Break down the polynomial equation

\frac{16x^4}{8x^2} + \frac{40x^3}{8x^2} - \frac{24x^2}{8x^2}

Step 2: Divide each piece by dividing the coeffients and subtracting the variables.

16 ÷ 8 = 2

x^{4} - x^{2} = x^{2} → 2x^{2}

40 ÷ 8 = 5

x^{3} - x^{2} = x → 5x

- 24 ÷ 8 = - 3

x^{2} - x^{2} = 1 → - 3

Step 3: Put the polynomial together

2x^{2} + 5x - 3

3 0
3 years ago
HELP ME ASAP!!!!
Sladkaya [172]

Answer:

the answer is m=11/16 you can just count if not then simplify what you get

5 0
3 years ago
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