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gulaghasi [49]
3 years ago
13

Solve for a in terms of b and c:3a+4b=c

Mathematics
1 answer:
MariettaO [177]3 years ago
8 0
We want a in terms of b and c:     <span>3a+4b=c

Isolate 3a on the left side:  3a = c - 4b
Divide all terms by 3:

                                             a = c/3 - 4b/3           (answer)</span>
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Use the Distributive Property on 45x-6
Alexandra [31]

Answer:

<h3>180</h3>

Step-by-step explanation:

<h3>45 × -6 = 45 × [10+(-6)]</h3><h3>45 × (10-6)</h3><h3>45 × 4</h3><h3>180</h3>
5 0
3 years ago
Write a standard form of a quadratic equation that has roots - 5/2 and 3.
lora16 [44]

Answer:

2x^2 - x - 15 = 0.

Step-by-step explanation:

In factor form this is

(x + 5/2)(x - 3) = 0

x^2 + 5/2x - 3x  - 15/2 = 0

x^2 - 1/2x - 15/2 = 0

Multiply through by 2:

2x^2 - x - 15 = 0.

6 0
3 years ago
What is 377,060 written in expanded form using exponents
Zinaida [17]
3x10^5
+7x10^4
+7x10^3
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7 0
3 years ago
Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the
KonstantinChe [14]

Answer:

The center of the circle is

(-\frac{3}{2},2)

Step-by-step explanation:

Let the equation of the circle be

x^2+y^2+2ax+2by+c=0, where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

0^2+0^2+2a(0)+2b(0)+c=0

\implies c=0

B(-3,0)

(-3)^2+0^2+2a(-3)+2b(0)+c=0

\implies 9+0-6a+0+c=0

\implies -6a+c=-9

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\implies -6a=-9

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C(1,2)

1^2+2^2+2a(1)+2b(2)+c=0

1+4+2a+4b+c=0

2a+4b+c=-5

Put the value of 'a' and 'c' to find 'b'

2(\frac{3}{2})+4b+0=-5

3+4b+0=-5

4b=-5-3

4b=-8

b=-2

Hence the center of the circle is

(-\frac{3}{2},2)

8 0
3 years ago
after two tests carol has a total score of 170. the score on her first test was 8 points higher than the score on her second tes
RoseWind [281]
X stands for the score of her first test
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3 years ago
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