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2 years ago

Solve for a in terms of b and c:3a+4b=c

1 answer:

8 0

We want a in terms of b and c: <span>3a+4b=c

Isolate 3a on the left side: 3a = c - 4b
Divide all terms by 3:

a = c/3 - 4b/3 (answer)</span>

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HEY CAN ANYONE PLS ANSWER MY MATH QUESTION!!!!1

Alenkinab [10]

Answer:

The blue and yellow macaw is 33 inches long.

Step-by-step explanation:

If the toucan is 22 inches long and it's two thirds the length of the macaw you can divide by two to find what one third is.

22 ÷ 2 = 11

So then you have to multiply by 3 to find what the full length is.

3 x 11 = 33 inches

Hope that helps and have a great day!

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2 years ago

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On the day a coffee shop first opened it had 140 customers 65% of the customers ordered a large coffee how manny customers order

madam [21]

91 patrons of the coffee shop ordered a large

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2 years ago

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draw an example of a shape that has at least one right angle one angle less than a right angle and one angle greater than a righ

MaRussiya [10]

That is not possible to make a triangle with a right angle and a acute angle because a acute triangle only has acute angles and a right triangle has a obtuse angle in it

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3 years ago

The scale drawing of a concrete pad has a length of 9.1 cm, a depth of 2.2 cm and a width of 3.8 cm.

pogonyaev

Answer:

242 cm

Step-by-step explanation:

1. Find the scale factor

A scale factor (SF) is the ratio of two corresponding lengths in similar figures.

SF = actual distance/scale distance

If the scale width is 3.8 cm,

SF = 418 cm/3.8 cm = 110

2. Calculate the actual depth

110 = actual depth/2.2 cm

Actual depth = 110 × 2.2 cm = 242 cm

8 0

3 years ago

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Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL

Mice21 [21]

Answer:

$KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47$

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

$\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}$

Also

$m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ}$ (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

$NL=45\tan 50^{\circ}$

$m\angle KLN=m\angle LNM=40^{\circ}$ (alternate interior angles)

$m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ}$ (angles KNL and KLN are complementary).

So,

$\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08$

and

$\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47$

3 0

2 years ago

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