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likoan [24]
4 years ago
14

Find surface area please

Mathematics
1 answer:
Bezzdna [24]4 years ago
3 0

Answer:

Hello the answer is 288. :D

Step-by-step explanation:

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Construct a confidence interval of the population proportion at the given level of confidence. x = 125, n = 250, 90 % confidence
madam [21]

Answer: 90% confidence interval would be (0.448, 0.552).

Step-by-step explanation:

Since we have given that

x = 125

n = 250

So, \hat{p}=\dfrac{x}{n}=\dfrac{125}{250}=0.5

We need to find the 90% confidence interval.

so, z = 1.64

So, interval would be

\hat{p}\pm z\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.5\pm 1.64\sqrt{\dfrac{0.5\times 0.5}{250}}\\\\=0.5\pm 0.0519\\\\=(0.5-0.0519,0.5+0.0519)\\\\=(0.448,0.552)

Hence, 90% confidence interval would be (0.448, 0.552)

3 0
4 years ago
9. The sum of two numbers is 30. If twice the bigger number is thrice the smaller, the
cluponka [151]

Answer:

12 & 18

If it’s asking only one it’s the smallest one i.e, 12.

6 0
3 years ago
If sin A = 3÷<br>5 then <br><br>find sin²A​
Korolek [52]

Answer:

12

Step-by-step explanation:

7 0
3 years ago
You purchase 26 "parking hours" that you can use over the next month to park
Nadusha1986 [10]

Answer:

The number of weekday hours are 5.

Step-by-step explanation:

<em>Let the number of weekday hours be "x".</em>

<em>The total week hours are 26, then number of weekend hours is (26-x) .</em>

<em>The charges for weekdays are $2 per hour and for weekends $10 per hour.</em>

The total money spent is $220.

(2)(x) + (26-x)(10) = 220

8x = 40

x = 5.

Thus weekday hours utilized are 5 hours, and weekend are (26-5) 21 hours.

4 0
3 years ago
Can someone please help me with this? I don’t understand what is given.
a_sh-v [17]

\bf BC=2BA\\ BE = 2BD \end{cases} \cfrac{BC}{BE}=\cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~BA}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~BD}\implies \cfrac{BC}{BE}=\cfrac{BA}{BD}\impliedby \begin{array}{llll} \textit{equal ratio of sides}\\ \textit{similar triangles} \end{array}

8 0
4 years ago
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