C. Inflation
If you require clarification on why, feel free to comment!
Answer:
The depreciation is $52,500
Explanation:
The formula to compute the depreciation under the straight-line method is shown below:
= ![\dfrac{(original\ cost - salvage\ value )}{Number\ of\ years}](https://tex.z-dn.net/?f=%5Cdfrac%7B%28original%5C%20cost%20-%20salvage%5C%20value%20%29%7D%7BNumber%5C%20of%5C%20years%7D)
= ![\dfrac{(\$225,000 - \$15,000)}{4\years}](https://tex.z-dn.net/?f=%5Cdfrac%7B%28%5C%24225%2C000%20-%20%5C%2415%2C000%29%7D%7B4%5Cyears%7D)
= $52,500
Under the straight-line method, the depreciation expense should be the same for the remaining useful life. Life of the equipment or machine should always be expressed in years, not in hours.
So, these usage of hours should be ignored.
Answer:
net income = $31,500
Explanation:
given data
collect tailoring fees = $43,300
paid expenses = $12,300
Depreciation expense= $2,500
Accounts receivable = $1,050
supplies increased = $4,300
liabilities increased = $2,350
to find out
accrual basis net income
solution
we get here net income by given expression that is
net income = tailoring fees - expenses paid + account receivable + supplies increased - liabilities increased - Depreciation expense .......1
put here value
net income = $43,300 - $12,300 + $1,050 + $4,300 - $2,350 - $2,500
net income = $31,500
Answer:
Future Value= $158,475.64
Explanation:
Giving the following information:
He saves $500 per month for 15 years and earns 7% by investing in the stock market through an index fund.
I assume we have to determine the value of the investment at the time of retirement.
<u>We need to use the following formula:</u>
FV= {A*[(1+i)^n-1]}/i
A= monthly deposit= 500
n= 15*12= 180
i= 0.07/12= 0.005833
FV= {500*[(1.005833^180) - 1]} / 0.006833
FV= $158,475.64