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Rufina [12.5K]
3 years ago
14

Please help me anyone, spent literally all afternoon on this problem, thank you guys!!:))

Mathematics
1 answer:
ki77a [65]3 years ago
4 0
How can I help you to if there is nothing to read or look at. you could have added a picture of even the problem in words instead of just writing me need help
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Use the distributive property to rewrite each expression. 3(-2x + 4)
Mila [183]

Answer:

-6x + 7

Step-by-step explanation:

you need to multiply 3 by each number individually.

(3) -2x + (3) 4

-6x + 7

hope that helps!

3 0
3 years ago
Kylie and her three friends equally didvided the cost to rent a movie for $4 and order sandwiches for a total of $15. They also
Vladimir [108]

16 dollars each person

7 0
3 years ago
Read 2 more answers
Multiple the polynomial (4x^2 + 4x + 6)(7x + 5)
Mazyrski [523]

Answer:

28 x³ + 48 x² + 62 x + 30

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the polynomial equation

            (4 x² + 4x +6)(7x+5)

Multiply

   ⇒   4 x² ( 7 x+5) + 4 x ( 7x+5) + 6 (7x+5)

  ⇒    28 x³ + 20 x² + 28 x² + 20 x + 42 x + 30

  ⇒    28 x³ + 48 x² + 62 x + 30

               

8 0
3 years ago
Find the midpoint of the line segment with the given endpoints.<br><br> Please help
leonid [27]
Answer: Midpoint: (3,-8)
(WORK SHOWN BELOW)

3 0
3 years ago
4) Sandeep, Hee, Sara, and Mohammad play euchre with a standard deck consisting of 24 cards (A, K, Q, J, 10, and 9 from each of
Keith_Richards [23]

Answer:

1.19685 × 10¹⁶

Step-by-step explanation:

From the given information.

Since each players receives 5 cards; then = 5 * 4 = 20

Now, the process to go about this is to first select 5 cards out of 24 that goes to player 1. Then from the remaining 19, we can select another 5 cards that goes to player 2, etc. until 4 cards are left, out of which one is remained faced up. Thus, the 4 sets of 5 cards selected can be shuffled in 4! ways.

∴

No fo ways = ^{24}C_5 \times ^{19}C_5 \times ^{14}C_5 \times ^{9}C_5 \times 4! \times ^{4}C_1

= \dfrac{24!}{5!(24-5)!}\times  \dfrac{19!}{5!(19-5)!}\times  \dfrac{14!}{5!(14-5)!}\times  \dfrac{9!}{5!4!}\times 4! \times \ \dfrac{4!}{1!(4-1)!}

= \dfrac{24!}{5!^4}\times 4

= 1.19685 × 10¹⁶

6 0
3 years ago
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