The correct representations of the given inequality are
–6x + 15 < 10 – 5x
and
A number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is <u>pointing to the right</u>. The correct options are the third and fourth options
<h3>Solving inequality</h3>
From the question, we are to solve the inequality
The given inequality is
–3(2x – 5) < 5(2 – x)
First, clear the brackets
–6x + 15 < 10 – 5x
NOTE: This is one of the correct representations of the inequality
Collect like terms
-6x + 5x < 10 - 15
-x < -5
Divide both sides by -1 and flip the sign
x > 5
Representing this on a number line, we get a number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is pointing to the right.
Hence, the correct representations of the given inequality are
–6x + 15 < 10 – 5x
and
A number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is <u>pointing to the right</u>. The correct options are the third and fourth options
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The equation for this would be 41/4 + 52/3 - 41/3= ?
So then you just change all the denominators to their lcm, which is 12 and multiply the numerator accordingly.
123/12 + 208/12 - 164/12 = 167/12
Answer:
-32
Step-by-step explanation:
Answer:
Step-by-step explanation:
AB = 8x + 5
BC = 5x² - 16
5x² - 16 = 8x + 5
5x² - 8x - 21 = 0
Quadratic formula
x = [8 ± √(8² – 4·5(-21))] / [2·5]
= [8 ± √484] / 10
= [8 ± 22] /10
= -1.4, 3
-1.4 is an extraneous solution.
x = 3
AB = 8x+5 = 29
AC = 58
For ΔABD, it is given that side AB is congruent to side CB, that ∠ABD is congruent to ∠CBD. In order to invoke the SAS Postulate, the remaining side(s) fo the triangles must be shown to be congruent. Those sides are BD and BD.
The appropriate choice is ...
... b. BD ≅ BD