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kifflom [539]
3 years ago
13

Hey i need help for 90÷40

Mathematics
2 answers:
Zinaida [17]3 years ago
6 0
2.25 is the answer got it now
Karo-lina-s [1.5K]3 years ago
3 0
When 90÷40 the answer will be 2.25

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hich function has a range of {y|y ≤ 5}? f(x) = (x – 4)2 + 5 f(x) = –(x – 4)2 + 5 f(x) = (x – 5)2 + 4 f(x) = –(x – 5)2 + 4
Brums [2.3K]

Answer:

f(x)=-(x-4)^2+5

Step-by-step explanation:

The function f(x)=-(x-4)^2+5 has  the vertex at (4,5).


Since a=-1\:, the graph of the function is a maximum graph.


The highest y-value is the y-coordinate of the vertex which is 5.


Therefore the range is {y|y\le 5}


Therefore the correct answer is B.


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3 years ago
Solve the equation 4y² = 7y​
Charra [1.4K]
The answer is Y=7/4
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Drag and drop formal proof. Prove the Polygon Exterior Angle Sum Theorem for the enclosed triangle, that is ∠1+∠2+∠3=360°
jasenka [17]

Answer:

The sum of all the external angles of a triangle is 360°.

Step-by-step explanation:

Let there are n sides in a polygon.

So, there are n internal angles in the polygon, let ∠i1, ∠i2, ∠i3, ..., ∠in are the measure of n internal angles of the polygon.

The measure of external angle corresponding to ∠i1,  ∠1= 180°-∠i1,

The measure of external angle corresponding to ∠i2, ∠2 = 180°-∠i2,

Similarly, the measure of external angle corresponding to ∠in, ∠n = 180°-∠in.

Now, the sum of all the external angles of the polygon,

(∠1+∠2+...+∠n)=(180°-∠i1)+(180°-∠i2)+...+(180°-∠in)

=(180°+180°+...n times)-(∠i1+∠i2+...+∠in)

=n x 180° - (∠i1+∠i2+...+∠in)

As ∠i1+∠i2+...+∠in is the sum of all the internal angles of the polygon.

So, the sum of all the external angles of the polygon =

(n x 180°) - (sum of all the internal angles of the polygon).

In the case of a triangle, n=3  and the sum of all the three internal angles, ∠i1+∠i2+∠i3 = 180°.

Therefore, the sum of all the external angles of a triangle,

∠1+∠2+∠3 =3x180°-(∠i1+∠i2+∠i3)

                 =540°=180°

                 =360°.

Hence, the sum of all the external angles of a triangle is 360°.

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If y+(x^2+x+1)(x^3-x-1), then y’(2)=
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Easy it’s y=learn it your self and pay attention you bum
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