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Answer:
The sum of the arithmetic progression is 2520
Step-by-step explanation:
The sum, Sₙ, of an arithmetic progression, AP, is given as follows;
Where;
n = The nth term of the progression
a = The first term = 100
d = The common difference = -2
Given that the last term = -10, we have;
-10 = 100 + (n - 1) ×(-2)
n = (-10 - 100)/(-2) + 1 = 56
Therefore, the sum of the 56 terms of the arithmetic progression is
Which gives;