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2 years ago

8

The population of Jalicia City was 24,000 people

2 answers:

MrRa [10]2 years ago

4 0

It might be a little tedious, but i think the easiest to understand is this way

first find what 4% of 24000 is. you can do this by simply multiplying 24000 by .04 which is 960. the new population for 2011 is 24960, and you again find what 4% of it is. Which is 998 people. In 2012, there will be 25958 people. Find 4% of that which is 1038 people. add it to 25958 & you get 26996 which is the estimate for how many people there will be in 2013. Not the easiest way, but i don't remember exactly how to do these problems, but this also works

notsponge [240]2 years ago

3 0

When using a calculator I got: 26996.736

However since it's people you should round to: 26997.

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2 years ago

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3 years ago

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3 years ago

Ask questions slove for x 5(x-3)=15

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Step-by-step explanation:

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3 years ago

Multiply. Check picture.

VashaNatasha [74]

The answer is $3x^4-13x^3-x^2-11x+6$ .

Solution:

Use algebraic identity: $a^m\times a^n=a^{m+n}$

For example: $x^2\times x=x^{2+1}=x^3$

Given expression $(x^2-5x+2)$ and $(3x^2+2x+3)$ .

To multiply these equations.

$(x^2-5x+2)\times(3x^2+2x+3)$

$=x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)$

$=(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)$

$=3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6$

Combine like terms together.

$=3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6$

$=3x^4-13x^3-x^2-11x+6$

$(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6$

Hence the answer is $3x^4-13x^3-x^2-11x+6$ .

3 0

3 years ago