Step-by-step explanation:
You need to solve for x.
You can do that by either setting both of the equations equal to each other. or Solve each one separately and subtract the EG equation from the EW to get GW
Step-by-step explanation:
5 = 12 Cross multiply
2.35 x
5x = 28.2 Divide 5 on both sides to isolate the variable
x = 5.64
<h3><u><em>
Hope this helps!!!</em></u></h3><h3><u><em>
Please mark as brainliest!!!</em></u></h3>
Answer is 3 seconds
When the bullet reaches the ground, ground being x in graph (and here its s which is = 0)
s = -16t^2 + 48t
s = 0, solve for t
0 = -16t^2 + 48t
0 = t ( -16t + 48)
0 = 16t ( - t + 3)
now you have two equation
0 = 16t and 0 = -t +3 ( you can look at the graph line touches x twice)
0 = 16 t
0 = t ( you know its false, because time = 0)
You are left with
0 = -t + 3
t = 3
It takes 3 seconds for the bullet to return to the ground.
// Hope this helps.
Answer:
i think D or B is the answer
Step-by-step explanation: