Equation:
distance + distance = 2250 miles
3x + 3(x-110) = 2250
6x - 330 = 2250
6x = 2580
x = 430 mph (rate of the westbound plane)
x-110 = 320 mph (rate of the eastbound plane)
PLS MARK BRAINLIEST!!!
To calculate the areas i’m pretty sure u need to do L x W so it would be .. 644 in2?
We are given equation: y=ln(x) .
And translation is 5 units down.
We know the rule of transformation f(x) = y + k, if k is greater than 0 it would move up or if k is less than 0, it would move down.
For the given translation 5 unit down, 5 should be less than 0.
Number less than 0 are negative numbers.
So, we need to add -5 in the given function to ln(x).
So, we would get the final equation for five units down as
y =ln(x) - 5.
Step-by-step explanation:
We want to find two things-- the speed of the boat in still water and the speed of the current. Each of these things will be represented by a different variable:
B = speed of the boat in still water
C = speed of the current
Since we have two variables, we will need to find a system of two equations to solve.
How do we find the two equations we need?
Rate problems are based on the relationship Distance = (Rate)(Time).
Fill in the chart with your data (chart attached)
The resulting speed of the boat (traveling upstream) is B-C miles per hour. On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour. The resulting speed of the boat (traveling downstream) is B+C miles per hour. Put this info in the second column in the chart. Now plug it into a formula! <u>Distance=(Rate)(Time) </u>Now solve using the systems of equations!
Answer:b
Step-by-step explanation: