Question

A car at rest accelerates at 6.50 m/s2 for 3.00 s. How far does the car travel in this time?

Answer 1

Answer:

The distance traveled by the car is 29.25 meters

Explanation:

The distance traveled by the car can be determine by means of the equations for a Uniformly Accelerated Rectilinear Motion:

$d = v_{0}t + \frac{1}{2}at^{2}$   (1)

Where $v_{0} = 0$ is the initial velocity, a is the acceleration and t is the time.

Since the car starts from rest, its initial velocity will be zero ($v_{0} = 0$):

$d = \frac{1}{2}(6.50 m/s^{2})(3.00 s)^{2}$

$d = 29.25 m$

So the distance traveled by the car is 29.25 meters.