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4 years ago

15

A girls walks 4 steps forward and then 3 steps backward. The girls distance walked is _______ steps and her displacement is

__________ steps.

2 answers:

kozerog [31]4 years ago

7 0

Answer:

A girls walks 4 steps forward and then 3 steps backward. The girls distance walked is <u>7</u> steps and her displacement is <u>1 </u>steps.

Explanation:

Distance can be defined as the total length of the path traveled from initial position to final position.

Displacement is the shortest distance between initial position and final position. It is difference between final position and initial position.

When a girl walks 4 steps forward and then 3 steps backwards, the distance traveled is: 4 + 3 = 7 steps

Displacement = 4 (forward)-3 (backwards) = +1 (forward)

OLEGan [10]4 years ago

4 0

Distance (skalar) = 4 + 3 = 7 step

displacement = 1 step

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The magnitude of the electric field and direction of electric field are $146.03\times10^{3}\ N/C$ and 75.36°.

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Second charge $q_{2}= 2.9\mu C$

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Using formula of electric field

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We need to calculate the horizontal electric field

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$E_{x}=36910.97=36.9\times10^{3}\ N/C$

We need to calculate the vertical electric field

$E_{y}=E_{2}+E_{1}\sin\theta$

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$E_{y}=141310.97=141.3\times10^{3}\ N/C$

We need to calculate the net electric field

$E_{net}=\sqrt{E_{x}^2+E_{y}^2}$

Put the value into the formula

$E_{net}=\sqrt{(36.9\times10^{3})^2+(141.3\times10^{3})^2}$

$E_{net}=146038.69\ N/C$

$E_{net}=146.03\times10^{3}\ N/C$

We need to calculate the direction of electric field

Using formula of direction

$\tan\theta=\dfrac{141.3\times10^{3}}{36.9\times10^{3}}$

$\theta=\tan^{-1}(\dfrac{141.3\times10^{3}}{36.9\times10^{3}})$

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