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2 years ago

The beat your doctor listens to through a sethoscope is the sound of the four values opening

Physics

1 answer:

djyliett [7]2 years ago

5 0

and closing .

The heart has 4 valves. They are what makes the lub-dub lub-dub sounds that can be heard from the chest.

The mitral valve is located between the left atrium and the left ventricle. It closes the left atrium to collect oxygenated blood from the lungs and opens to pass it on to the left ventricle.

The tricuspid valve is located between the right atrium and the right ventricle. It closes the right atrium to hold unoxygenated blood and opens to pass it on to the right ventricle ensuring a one way flow.

The aortic valve is located between the aorta and the left ventricle. It closes the left ventricle and opens to the aorta to pass on the oxygen-rich blood to the body.

The pulmonary valve is located between the pulmonary artery and the right ventricle. It closes off the right ventricle and opens to pass on unoxygenated blood to the lungs.

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The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: =E−Ryn2 In this equation Ry stands for

skelet666 [1.2K]

Answer:

λ = 162 10⁻⁷ m

Explanation:

Bohr's model for the hydrogen atom gives energy by the equation

$E_{n}$ = - k²e² / 2m (1 / n²)

Where k is the Coulomb constant, e and m the charge and mass of the electron respectively and n is an integer

The Planck equation

E = h f

The speed of light is

c = λ f

E = h c /λ

For a transition between two states we have

$E_{n}$ - $E_{m}$ = - k²e² / 2m (1 / $n_{f}$ ² -1 / $n_{i}$ ²)

h c / λ = -k² e² / 2m (1 / $n_{f}$ ² - 1/ $n_{i}$ ²)

1 / λ = (- k² e² / 2m h c) (1 / $n_{f}$ ² - 1/ $n_{i}$ ²)

The Rydberg constant with a value of 1,097 107 m-1 is the result of the constant in parentheses

Let's calculate the emission of the transition

1 /λ = 1.097 10⁷ (1/10² - 1/8²)

1 / λ = 1.097 10⁷ (0.01 - 0.015625)

1 /λ = 0.006170625 10⁷

λ = 162 10⁻⁷ m

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