Question

Two small pitchers and one large pitcher can hold 8 cups of water. One large pitcher minus one small

Answer 1

Answer:

20 cups

Step-by-step explanation:

Let the small pitchers be given by s

and the larger pitchers by l

According to the given information:

$2s + l = 8....(1) \\ and \\ l - s = 2 \\ l = s + 2...(2) \\ substituting \: l = s + 2 \: in \: equation \: (1) \\ 2s + s + 2 = 8 \\ 3s = 8 - 2 \\ 3s = 6 \\ s = \frac{6}{3} \\ \huge \red{ s = 2} \\ substituting \: s = 2 \: in \: equation \: (2) \\ l = 2 + 2 \\ \huge \purple{ l = 4}\\\\Now\\ 3l +4s \\= 3\times 4+4\times 2\\= 12 +8\\= 20\: cups$

So, 3 large pitchers and 4 small pitchers hold 20 cups of water.