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Reika [66]
3 years ago
15

If you removed 1/4" of stock from a 1" piece of wood, what would you have remaining?

Mathematics
1 answer:
stellarik [79]3 years ago
4 0
3/4” of a inch of stock is left
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A fuel-tanker's tank is 50 feet long and has a diameter of seven feet. Determine the surface area of the fuel tank.
Bezzdna [24]

Answer:

1176.679ft²

Step-by-step explanation:

<u>The question is on surface area of a cylindrical fuel tank</u>

Equation for surface area of a cylinder

S.A = 2\pirh +2\pir²

where r is the radius of cylinder and h is height of cylinder

Diameter=7'⇒r=3.5' and h=50'

Surface Area= 2×3.142×3.5×50 + 2×3.142×3.5×3.5

S.A=1099.7+76.979=1176.679ft²

6 0
3 years ago
Read 2 more answers
Find the volume of the cylinder.<br> Either enter an exact answer in terms of or use 3.14
kow [346]

Answer: 400

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

4+\sqrt{6x}

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

8 0
3 years ago
If it takes 10 women 8 days to make 3 treehouses, how many days does it take 6 women to make 36 treehouses
umka2103 [35]

Answer:

160 days

Step-by-step explanation:

If it takes 8 days with 10 women to make 3 tree houses, then the rate of woman per tree house is 3/80. Multiplying this by 6 and dividing by 36, you get a rate of 1/160 or 160 days. Hope this helps!

6 0
3 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (
Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...

So, for the given function y = 6 sec(3x), we get:

y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

6 0
3 years ago
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