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2 years ago

Equation of a line pass through origin in called

Mathematics

1 answer:

mafiozo [28]2 years ago

7 0

The equation of a straight line with gradient m passing through the origin is:

$\displaystyle y=mx$

The line passes through the origin, so the y-intercept is $0$

$\displaystyle y=mx+b$

$\displaystyle y=mx+0$

$\displaystyle y=mx$

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Ieda and Thanh both offer piano lessons. Ieda charges an initial fee of $8.50 and an hourly rate of $11.00. Thanh charges an ini

Verizon [17]

Answer:

after 3 hours of instruction.

Step-by-step explanation:

First, start by setting up the equation.

Leda charges an initial fee, meaning this fee is only going to be one time. However, there is an hourly rate of 11. Since we do not know how many hours these piano lessons are going to last, we put a variable (I will use x), after this number.

The initial fee is 8.50. There needs to be a variable after 11 because that is the number we don't know.

The equation for Leda's lessons are 8.50+11.00x.

Now, we need to find out what the equation for Thanh's lessons are going to be, because we're going to be setting both equations equal to each other to find out when they cost the same. At the moment both equal each other, is when they are the same amount.

Thanh's equation also has an intial fee and an hourly rate. So, the equation will be

10.00+10.50x.

Now we solve.

8.50+11.00x = 10.00+10.50x

First, subtract from both sides. We will do the numbers without variables first.

8.50+11.00x = 10.00+10.50x

-8.50 -8.50

____________________

0 +11.00x = 1.50 +10.50x

Then, subtract the x's. (taking away the zero because it is equivalent to nothing)

11.00x = 1.50 +10.50x

- 10.50x -10.50x

__________________

0.50x = 1.50

Lastly, to find out the answer, we divide.

1.50/0.50= 3.

To check your answer, you can plug into the original equation.

8.50+11.00 times 3 = 10.00+10.50 times 3

Both sides equal 41.50, meaning they are equal to each other!

7 0

2 years ago

Read 2 more answers

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30 What score is necessary to reach

nlexa [21]

Answer:

A score of 150.25 is necessary to reach the 75th percentile.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.

This means that $\mu = 130, \sigma = 30$

What score is necessary to reach the 75th percentile?

This is X when Z has a pvalue of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 130}{30}$

$X - 130 = 0.675*30$

$X = 150.25$

A score of 150.25 is necessary to reach the 75th percentile.

7 0

3 years ago

For the equation 3x - 5y = -3, what is the value of y when x is 1? 6/5 -6/5 5/6

babymother [125]

Answer:

$\frac{-6}{5}$

Step-by-step explanation:

$3(1) - 5y = -3\\3 - 5y = -3\\-3 \\5y = -6\\/5 \\\\\frac{-6}{5}$

3 0

3 years ago

Read 2 more answers

Will uses 36.12 ounces of milk to make 9 shakes. About how much milk is in each shake?

bonufazy [111]

Answer:

About 4 oz

Step-by-step explanation:

36.12 is founded to 36. 36 oz /9 milkshakes is 4oz per milkshake.

6 0

2 years ago

Read 2 more answers

the graph of y=e^tanx-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point? I g

Svetlanka [38]

Y = e^tanx - 2

To find at which point it crosses x axis we state that y= 0

e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061

to find slope at that point first we need to find first derivative of funtion y.

y' = (e^tanx)*1/cos^2(x)

now we express x = 0.6061 in y' and we get:
y' = k = 2,9599

3 0

2 years ago