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2 years ago

14

What is the formula area for a triangle?

1 answer:

Mazyrski [523]2 years ago

5 0

Answer:

base x height divided by 2

Step-by-step explanation:

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Rudik [331]

Answer:

i cant even see properly

Step-by-step explanation:

6 0

2 years ago

Travis has a budget of $300 that he can spend on perennial flowers and at least 6 annual flowers. Perennial flowers are 18 dolla

boyakko [2]

Answer:

18x + 15y ≤ 300
x ≥ 0; y ≥ 6

Step-by-step explanation:

Variables are defined in the problem statement.

18x +15y ≤ 300 . . . . total budget

y ≥ 6 . . . . . . . . . . . . minimum number of annuals

x ≥ 0 . . . . . number of perennials cannot be negative

This system of inequalities describes the situation.

6 0

3 years ago

Helppp! idk why its needs to be 20 charactes so i wrote this

marin [14]

This should be 1.35, sorry if it’s wrong

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2 years ago

Read 2 more answers

Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

(c) $4(m+n)=4m+4n$ (using $a(b+c)=ab+ac$ )

(d) $3(5-q)=15-3q$ (using $a(b-c)=ab-ac$ )

(e) $5(2c+1)=10c+5$ (using $a(b+c)=ab+ac$ )

(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

(i) $2(6a-4b+3)=2((6a-4b)+3)$

⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

(j) $6(m+n+p)=6((m+n)+p)$

⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

(m) $n(4-n)=4n-n^2$ (using $a(b-c)=ab-ac$ )

(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

(p) $2x(x+5)=2x^2+10x$ (using $a(b+c)=ab+ac$ )

(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

(s) $4a(3b+2c)=12ab+8ac$ (using $a(b+c)=ab+ac$ )

(t) $5p(4p-5q)=20p^2-25pq$ (using $a(b-c)=ab-ac$ )

6 0

3 years ago

Are the associative properties true for all integers

Ymorist [56]

Associative property works in addition and multiplication.
Associative property in Addition: (a + b)+ c = a + (b + c)
Associative property in Multiplication: (a x b) x c = a x (b x c)
Associative property in Subtraction: (a - b) - c is not equal to a - (b - c)
Associative property in Division: (a divided by b) divided by c is not equal to a divided by (b divided by c).
Thus, associative property is not true for all integers.

3 0

3 years ago