Answer:
Here we have the relation:
m = 140*h
Where m is the distance in miles, and h is time in hours.
And we want to complete a table like:
![\left[\begin{array}{ccc}in, h&out, m\\&\\&\\&\\&\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Din%2C%20h%26out%2C%20m%5C%5C%26%5C%5C%26%5C%5C%26%5C%5C%26%5Cend%7Barray%7D%5Cright%5D)
The way to complete this, is to evaluate the function:
m = 140*h
in different values of h, and then record both values of h and m in the table.
Let's use values of h that increase by 0.5, then:
if h = 0.5
m = 140*0.5 = 70
We have the pair: h = 0.5, m = 70
if h = 1
m = 140*1 = 140
We have the pair: h = 1, m = 140
if h = 1.5
m = 140*1.5 = 210
Then we have the pair h = 1.5, m = 210
if h = 2
m = 140*2 = 280
We have the pair: h = 2, m = 280
Now we can complete the table, and it will be:
![\left[\begin{array}{ccc}in, h&out, m\\0.5&70\\1&140\\1.5&210\\2&280\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Din%2C%20h%26out%2C%20m%5C%5C0.5%2670%5C%5C1%26140%5C%5C1.5%26210%5C%5C2%26280%5Cend%7Barray%7D%5Cright%5D)
Answer: y = (x +2)² + 5
<u>Step-by-step explanation:</u>
y = a(x - h)² + k <em>where "a" is the leading coefficient and (h, k) is the vertex</em>
Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a": (x, y) = (0, 9) and (h, k) = (-2, 5)
y = a(x - h)² + k
9 = a(0 - (-2))² + 5
9 = a(0 + 2)² + 5
9 = a(2)² + 5
<u>-5 </u> <u> -5 </u>
4 = a(4)
<u>÷4 </u> <u> ÷4 </u>
1 = a
Next, plug in "a" and the vertex (h, k):
y = a(x - h)² + k
y = 1(x +2)² + 5
y = (x +2)² + 5
Answer:
dsdsdsdsdsdssdsddddddddd
Step-by-step explanation:
Answer: Nueve
Step-by-step explanation: Si cuadras el número nueve obtendrás ochenta y uno. Agregue once a eso y obtendrá noventa y uno.
¿Brainliest por favor?
1km=1000metres
15km=15000 metres
15000/600=25
25-1=24 (minus the last one)
hope this helps :)
