Anyone know what the answer is?

A zip line starts on a platform that is 40 meters above the ground. The anchor for the zip line is 198 horizontal meters from th

Damm [24]

Answer:

Solution given:

perpendicular distance =height [p]=40m

base or horizontal distance [b]=198m

Hypotenuse or zip line [h]=?

Now

By using Pythagoras law

h²=p²+b²

h²=40²+198²

h=√40804

h=202m

So the Zip line is 202m long.

7 0

3 years ago

10.The school needs to purchase a new refrigerator for student rewards. Lowes and Sears have the model

vovangra [49]

Lowe’s would be a better. They would be $10 cheaper even after the delivery fee.

8 0

3 years ago

PLEASE HELP I MIGHT FAIL MATH. For a charity event, raffle tickets are printed such that they have a vowel (excluding y) as the

Radda [10]

Answer:

Step-by-step explanation:

Remark

You better be issuing a very small number of tickets.

Tickets vowels: a e i o u

Primes < 10: 2 3 5 7

Probability(e and 5) = 1/5 * 1/4 = 1/20

Answer: 1/20

Answer:0.05

You should probabily give 0.05 as your answer.

8 0

2 years ago

two arcs of concentric circles are intercepted by the same central angle. the resulting arc length of the arc of the larger circ

Bond [772]

the complete question in the attached figure

Let
A°-----------> the same central angle

For the larger circle
length of larger circle=2*pi*r-------> 2*pi*12-----> 75.36 m

360° (full circle) has a length of------------> 75.36 m
A°-----------------------------------> 16 m
A°=(16)*360/75.36--------> A=76.43°

For the smaller circle
length of smaller circle=2pi*r-------> 2*pi*7.5-----> 47.1 m

360° (full circle) has a length of------------> 47.1 m
76.43°-----------------------------------> X
X=76.43*47.1/360-----> X=10 m ----> length arc of the smaller circle

the answer is
the length arc of the smaller circle is 10 m

3 0

3 years ago

Otto invests $1,000 at age 20. Otto wants theinvestment to be worth $4,000 by age 30. Ifinterest is compounded continuously, wha

AveGali [126]

$r\approx0.139$

1) Since this is a Continuously Compounded operation in a 10 yrs period, then we can write out the following equation:

$\begin{gathered} A=Pe^{rt} \\ \end{gathered}$

2) Plugging into the equation the given data and since Otto is 20 yrs old and he plans to get $4,000 in ten years, we can write out:

$\begin{gathered} 4000=1000e^{\mleft\{10r\mright\}} \\ \frac{4000}{1000}=\frac{1000e^{10r}}{1000} \\ 4=e^{10r} \\ \ln (4)=\ln (e)^{10r} \\ 10r=\ln (4) \\ r=\frac{\ln (4)}{10} \\ r=0.1386 \end{gathered}$

3) Thus the rate Otto needs is

$r=0.1386\approx0.139$

Note that since the 0.1386 the six here is greater than 5 then we can round up to the next thousandth, in this case: 0.139. For the 0.1386 is closer to 0.139 (0.004) than to 0.138 (0.006).

Or 13.9%

8 0

1 year ago