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Ostrovityanka [42]
3 years ago
5

Brody is purchasing some tools for his workshop. He has a budget of $120 and needs to buy at least 14 tools. Each hammer costs $

10, and each wrench costs $6. If the solution region represents the number of hammers and wrenches that Brody can buy given his budget, determine which graph represents the solution set to the system of inequalities representing this situation. A. B. C. D.
Mathematics
1 answer:
STatiana [176]3 years ago
5 0

Answer:

For this case, the first thing we must do is define variables:

x: number of hammers

y: number of wrenches

We write the system of inequations:

10x + 6y <= 120

x + y> = 14

Step-by-step explanation:

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Please help soon!!! I can’t figure this out! ;-; I just need this answer :(
kodGreya [7K]
10^2 + 4 * (6 + 3) - 27 ÷ (9 - 6) = 127

=100 + 4 * 9 - 27 ÷ 3
multiplication & division before addition and subtraction (order of operations rules, PEMDAS)

100 + 36 - 9= 127
136 - 9= 127
127= 127

Place a set of parentheses around (6+3) and (9-6).

Hope this helps! :)
4 0
3 years ago
What number is the same as 3 tens and 12 ones.​
Arlecino [84]

Answer:

42 because 3 tens is 30 and 12 ones is 12. so you do 30 + 12 = 42

5 0
3 years ago
Read 2 more answers
If Nancy needs 3/1/4 cups of oatmeal,how many 1/4 cups of oatmeal will she use
PIT_PIT [208]
The answer is 12 1/4. how I got my answer.

Their are 4 quarters to a whole, so that means all I have to do is multiply 4×3=12, then add 1/4+12= 12 1/4.

I hope this helps!
8 0
3 years ago
You and your friend are painting the walls in your apartment. You estimate
Novay_Z [31]

Answer:

Honestly I dont know man, Im pretty sure you already  found thee answer already since this was in April

Step-by-step explanation:

3 0
3 years ago
For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability. 
7 0
3 years ago
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