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3 years ago

10

What kind of triangle is 6, 8, and 9

1 answer:

Vika [28.1K]3 years ago

5 0

Answer:

equiangular -right -obtuse -acute.

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2p + 8 = 20-P<br> 2p + 8 + p = 20-p+p<br> 3p + 8 = 20<br><br> what’s the value of p ?

adell [148]

The answer to p is 4

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3 years ago

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Select the values that make the inequality h < 1 true.

kari74 [83]

H = 0 and all negative numbers

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3 years ago

Can someone please explain!!<br> Evaluate each expression for r= -3 and s= 5.<br> r=-3<br> Answer=

olga nikolaevna [1]

It is asking you to substitute or plug in the values.

Example:

Evaluate 3r(s+3) if r = -3 and s = 5

See that r? It means that you put in -3 in place of the r, and you put 5 in place of the s so it looks like this:

3*-3(5+3)

Now solve that using order of operations and you should get
-9*(5+3) (don't forget that your'e distributing here FIRST then add)

-45+-27

-72

That's how you solve an expression like that. This is only an EXAMPLE. Hope it helped.

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3 years ago

A container initially containing10 L of water in which there is 20 g of salt dissolved. A solution containing 4 g/L of salt is p

Kay [80]

Answer:

$A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196$

Step-by-step explanation:

For this case the solution flows at a rate of 2L/min and leaves at 1L/min. So then we can conclude the volume is given by $V= 10 +t$

Since the initial volume is 10 L and the volume increase at a rate of 1L/min.

For this case we can define A as the concentration for the salt in the container. And for this case we can set up the following differential equation:

$\frac{dA}{dt}= 4 \frac{gr}{L} *2 \frac{L}{min} - \frac{A}{10+t}$

Because at the begin we have a concentration of 8 gr/L and would be decreasing at a rate of $\frac{A}{10+t}$

So then we can reorder the differential equation like this:

$\frac{dA}{dt} +\frac{A}{10+t} =8$

We find the solution using the integration factor:

$\mu = -\int \frac{1}{10+t} dt = -ln(10+t)$

And then the solution would be given by:

$A = e^{-ln (10+t)} (\int e^{\int \frac{1}{10+t} dt})$

And if we simplify this we got:

$A= \frac{1}{10+t} (c + \int (10 +t) 8 dt)$

And after do the integral we got:

$A= \frac{c}{10+t} +4 (10 +t)$

And using the initial condition t=0 A= 20 we have this:

$20 = \frac{c}{10} +40$

$c= -200$

So then we have this function for the solution of A:

$A= \frac{-200}{10+t} +4 (10 +t)$

And now replacinf t= 40 we got:

$A(40)= \frac{-200}{10+40} +4 (10 +40)=-4+200 = 196$

8 0

3 years ago

How do o solve this equation? 4(3x - 10) + 7 = 15

Rama09 [41]

X=4 because first u distruste and add the numbers then add 33 to both side

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3 years ago

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