Answer:
D. -9
Step-by-step explanation:
Answer:
Option E is correct.
The expected number of meals expected to be served on Wednesday in week 5 = 74.2
Step-by-step Explanation:
We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.
Week
Day 1 2 3 4 | Total
Sunday 40 35 39 43 | 157
Monday 54 55 51 59 | 219
Tuesday 61 60 65 64 | 250
Wednesday 72 77 78 69 | 296
Thursday 89 80 81 79 | 329
Friday 91 90 99 95 | 375
Saturday 80 82 81 83 | 326
Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952
Total number of meals served at lunch on Wednesdays over the 4 weeks = 296
Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443
Total number of meals expected to be served in week 5 = 490
Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3
Checking the options,
74.3 ≈ 74.2
Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2
Hope this Helps!!!
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Answer:
Hence x = y = 2
Step-by-step explanation:
Using the SOH CAH TOA identity
Hypotenuse = 2√2
Opposite = x
theta = 45
Sin theta = opp/hyp
Sin 45 =x/2√2
1/√2 = x/2√2
x = 2√2 * 1/√2
x = 2
To get y we will use the pythagoras theorem;
(2√2)² = x² +y²
(2√2)² = 2²+y²
8 = 4 + y²
y² = 8-4
y² = 4
y = √4
y = 2
Hence x = y = 2
