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xxTIMURxx [149]
2 years ago
12

The end points of Line GH are G (10,2) and H(4,8). Find the coordinates of the midpoint M.

Mathematics
1 answer:
nikitadnepr [17]2 years ago
7 0

Answer:

(10-4)/2 , (2-8)/2

6/2 , -6/2

Midpoint = (3,-3)

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Which number is greater and by how much? a decreased by 50% and then increased by 50% of the result
zaharov [31]

Answer:

Let's assume the number is 100 now it is increased by 50% that means

100+ (50/100)*100

100+50=150

Now it is decreased by 25% that means

150- (25/100)*150

150–37.5=112.5

Total percentage increase ={(112.5–100)/100}*100

=12.5%

Step-by-step explanation:

7 0
2 years ago
Please help me!!!<br> asap please please please
mamaluj [8]

Answer:

I'm pretty sure its the 3rd answer

8 0
3 years ago
Read 2 more answers
Mrs.Lamb’s favorite candy bar weight 3 ounces. If a box contains 150 of these candy bars, what is the weight, In pounds, of this
Bumek [7]

Answer:

28.125

Step-by-step explanation:

A bar weights 3 ounces, she has a box of 150 so you multiply

150 times 3 = 450

well one pound equals 16 ounces, so you divide

450 divide by 16 = 28.125

5 0
3 years ago
Identify the type of function represented by... please help
Vladimir [108]

Answer:

Exponential decay.

Step-by-step explanation:

You can use a graphing utility to check this pretty quickly, but you can also look at the equation and get the answer. Since the function has a variable in the exponent, it definitely won't be a linear equation. Quadratic equations are ones of the form ax^2 + bx + c, and your function doesn't look like that, so already you've ruled out two answers.

From the start, since we have a variable in the exponent, we can recognize that it's exponential. Figuring out growth or decay is a little more complicated. Having a negative sign out front can flip the graph; having a negative sign in the exponent flips the graph, too. In your case, you have no negatives; just 2(1/2)^x. What you need to note here, and you could use a few test points to check, is that as x gets bigger, (1/2) will get smaller and smaller. Think about it. When x = 0, 2(1/2)^0 simplifies to just 2. When x = 1, 2(1/2)^1 simplifies to 1. Already, we can tell that this graph is declining, but if you want to make sure, try a really big value for x, like 100. 2(1/2)^100 is a value very very very veeery close to 0. Therefore, you can tell that as the exponent gets larger, the value of the function goes down and gets closer and closer to zero. This means that it can't be exponential growth. In the case of exponential growth, as the exponent gets bigger, your output should increase, too.

3 0
3 years ago
WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

where the c_i are positive integer coefficients from the binomial expansion. By Euler's theorem,

\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9

so that

32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9

7 0
2 years ago
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