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3 years ago

Maria ran 17 miles at an average speed of 5 miles per hour.

1 answer:

8 0

I think this is what it's asking for...

a) 17 is the total amount ran
5 is the number of miles
x is the hours (which is unknown)
you have to find x. the problem says that there are 5 miles per hour so your x would go with your 5. the 17 stays on the opposite side of the =
17=5x

b) to find the amount of time (x) just solve for x
17=5x is your equation
you now have to isolate the x (do this by dividing 5 on both sides of the equation)
5/x= x alone
17/5=3.4
3.4=x
* remember that x is hours in this problem, so round if you need too

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Find the equation of line b described below, in slope-intercept form

Serjik [45]

Given:

Line a is perpendicular to line b .

Line a passes through the points (1,-8) and (9,-12) .

Line b passes through the point (-8, -16).

To find:

The equation of b.

Solution:

Line a passes through the points (1,-8) and (9,-12) . So, slope of line a is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m_a=\dfrac{-12-(-8)}{9-1}$

$m_a=\dfrac{-12+8}{8}$

$m_a=\dfrac{-4}{8}$

$m_a=-\dfrac{1}{2}$

Product of slopes of two perpendicular lines is -1.

$m_a\times a_b=-1$

$-\dfrac{1}{2}\times a_b=-1$

$b=2$

Slope of line b is 2.

If a line passing through a point $(x_1,y_1)$ with slope m, then equation of line is

$y-y_1=m(x-x_1)$

Line b passing through (-8,-16) with slope 2. So, equation of line b is

$y-(-16)=2(x-(-8))$

$y+16=2(x+8)$

$y+16=2x+16$

Subtract 16 from both sides.

$y=2x$

Therefore, the equation of line b is $y=2x$ .

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2 years ago

0.1325 to thr hundredths

viktelen [127]

.13 hope this helps :D

6 0

2 years ago

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Rewrite the expression with the given base. 25^3x with a base of 5.

svp [43]

$Use\ (a^n)^m=a^{nm}\\\\25^{3x}=(5^2)^{3x}=5^{2\cdot3x}=5^{6x}$

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3 years ago

What is the value of the underlined digit in the number 126,847?

lapo4ka [179]

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2 years ago

Airport offers 2 shuttles that run on different schedules.if they both leave airport at 4:00 p.m. what time will they next leave

koban [17]

basically have to find the lowest common multiply of 6 and 9.

The LCM of 6 minutes and 9 minutes = 18 minutes

so if they both leave at 4:00 p.m., they would then both leave at 4:18 p.m.

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2 years ago