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sweet-ann [11.9K]
3 years ago
7

How do I solve operations with absolute value [10-11]-[15]

Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0
[10-11] - [15]
=[21] -[15]
=  [6]

anything inside the absolute bracket would have to remain positive, anything outside wouldn't change 
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There is no smallest positive rational number because, if there were, then it could be divided by two to get a smaller one. EXPL
Gennadij [26K]

Answer:

Since a/2⁽ⁿ ⁺ ¹⁾b <  a/2ⁿb,  we cannot find a smallest positive rational number because there would always be a number smaller than that number if it were divided by half.

Step-by-step explanation:

Let a/b be the rational number in its simplest form. If we divide a/b by 2, we get another rational number a/2b. a/2b < a/b. If we divide a/2b we have a/2b ÷ 2 = a/4b = a/2²b. So, for a given rational number a/b divided by 2, n times, we have our new number c = a/2ⁿb where n ≥ 1

Since \lim_{n \to \infty} \frac{a}{2^{n}b } = a/(2^∞)b = a/b × 1/∞ = a/b × 0 = 0, the sequence converges.

Now for each successive division by 2, a/2⁽ⁿ ⁺ ¹⁾b <  a/2ⁿb and

a/2⁽ⁿ ⁺ ¹⁾b/a/2ⁿb = 1/2, so the next number is always half the previous number.

So, we cannot find a smallest positive rational number because there would always be a number smaller than that number if it were divided by half.

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3 years ago
The following tile floor pattern is made of 36 square tiles.
Ierofanga [76]

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Perhaps you mean "slope-intercept" form. Solve for y and reduce the fractions.
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What is 20% of 148<br> Anyone know
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Step-by-step explanation:

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