Answer:
32.
Step-by-step explanation:
This is an arithmetic sequence with first term a1 = -6 and common difference 2.
an = a1 + d(n - 1)
a20 = -6 + 2(20-1) = 32
Answer:
f^(-1)(x) = -3x/(3x-3)
Step-by-step explanation:
1) replace f(x) by y
● y = 3x/(5x+3)
2) exchange x and y
● y = 3x/(5x+3)
● x = 3y / (3y +3)
3) solve for y
● x = 3y / (3y +3)
● x (3y +3) = 3y
● 3xy + 3x = 3y
● 3xy - 3y = -3x
● y (3x - 3) = -3x
● y = -3x /(3x-3)
4) replace y with f^(-1)(x)
● y = -3x/(3x-3)
● f^(-1)(x) = -3x/(3x-3)
Where is it shown? You need to attach a picture or something.


Solve for y

let's put our equation first

Flip the equation

Now follow the rule of 


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add
to both sides

Divide both sides by 


would equal 
Consecutive numbers would be like 2 and 3, or 7 and 8.
All we need to do is keep multiplying pairs of consecutive numbers until we get above 50.
1 × 2 = 2 (that's one.)
2 × 3 = 6 (two)
3 × 4 = 12 (three)
4 × 5 = 20 (four)
5 × 6 = 30 (five)
6 × 7 = 42 (six...)
<em>7 × 8 = 56 > 50</em>
We have a total of 6 numbers that equal the product of 2 consecutive intergers<em>
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