Which equations are in standard form? Check all that apply y = 2x + 5 2x + 3y = –6 –4x + 3y = 12 y = y equals StartFraction 3 Ov
2 answers:
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Simplifying h(x) gives
h(x) = (x² - 3x - 4) / (x + 2)
h(x) = ((x² + 4x + 4) - 4x - 4 - 3x - 4) / (x + 2)
h(x) = ((x + 2)² - 7x - 8) / (x + 2)
h(x) = ((x + 2)² - 7 (x + 2) - 14 - 8) / (x + 2)
h(x) = ((x + 2)² - 7 (x + 2) - 22) / (x + 2)
h(x) = (x + 2) - 7 - 22/(x + 2)
h(x) = x - 5 - 22/(x + 2)
An oblique asymptote of h(x) is a linear function p(x) = ax + b such that
In the simplified form of h(x), taking the limit as x gets arbitrarily large, we obviously have -22/(x + 2) converging to 0, while x - 5 approaches either +∞ or -∞. If we let p(x) = x - 5, however, we do have h(x) - p(x) approaching 0. So the oblique asymptote is the line y = x - 5.
Answer:
- A'(-3, 12)
- B'(9, 6)
- C'(-6, -6)
Step-by-step explanation:
Dilation about the origin multiplies each coordinate value by the dilation factor.
For dilation factor k, the new coordinates are ...
(x, y) ⇒ (kx, ky)
Your dilation factor is 3, so the transformation is ...
(x, y) ⇒ (3x, 3y)
A(-1, 4) ⇒ A'(-3, 12)
B(3, 2) ⇒ B'(9, 6)
C(-2, -2) ⇒ C'(-6, -6)
