What is the slope of the line passing through the points (2, −5) and (4, 1)? 2 −4/5 5/4 3
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Answer:
<h2>See the explanation.</h2>Step-by-step explanation:
Sin2α = 2SinαCosα.
Cos2α = (Cosα)^2 - (Sinα)^2.
Sin4α can be written as Sin2(2α).
Similarly Cos4α can be written as Cos2(2α).
It is given that tanα=3.
Sinα(Sinα) = [
], the values either be both positive or both negative, as the value of tanα is positive only on first and third quadrant.
Sin4α = .
Cos4α =