Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.
Answer:
The answer is when we rotating something 90 degrees clockwise about the orgin
(x,y) goes to (y,-x)
To determine which relation is a function, we can perform something called the vertical line test. We cover the graph in repeating vertical lines and if one vertical line connects with more than one point of the relation, the relation is not a function.
The relation in the bottom right corner is the only relation that passes the vertical line test.
E=3.33
3.33(333)= $1,108.89
Answer:
0.56
Step-by-step explanation:
14 divided by 25 is 0.56
