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12345 [234]
3 years ago
7

Need help with a statistics question anything will help

Mathematics
1 answer:
stealth61 [152]3 years ago
3 0
WHAT THE F-

why are the the questions fat paragraphs my dude 
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Divide .5 4 then do the rest
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Find the future value if £7400 is<br> invested for 6 years at 12.8% p.a.
Free_Kalibri [48]

Answer:

5683.2 Euro's

Step-by-step explanation:

i=

p=7400 Euro's

r=12.8*1/100

t=6yrs

I=P*R*T

7400*12.8/100*6

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3 years ago
In a school of 300 students, 110 offered French, 110 Hausa language, 180 history, 40 French and Hausa, 50 Hausa and history, 60,
Julli [10]

Answer:

Step-by-step explanation:

a

8 0
3 years ago
Following a recent dramatic drop of 500 points in the Dow Jones Industrial Average, a poll conducted for the Associated Press fo
Strike441 [17]

Using statistical concepts, it is found that the term that best describes the number 92% is:

a. statistic.

  • If the information is taken from a sample, it is called a statistic.
  • If the information is taken from a population, it is called a parameter.

In this problem, 92% of those polled said that a year from now their family financial situation will be as good as it is today or better, that is, 92% of the sample, hence, it is a statistic, and option a is correct.

To learn more about the concepts of statistic and parameter, you can take a look at brainly.com/question/16840464

5 0
2 years ago
A forester studying diameter growth of red pine believes that the mean diameter growth will be different from the known mean gro
-Dominant- [34]

Answer:

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

Step-by-step explanation:

Data given and notation  

\bar X=1.6 represent the sample mean

s=0.46 represent the sample deviation

n=32 sample size  

\mu_o =1.35 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 1.35 in/year, the system of hypothesis would be:  

Null hypothesis:\mu =1.35  

Alternative hypothesis:\mu \neq 1.35  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

P-value  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

5 0
3 years ago
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