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Yuri [45]
4 years ago
11

*WILL MARK BRAINLIEST*

Mathematics
2 answers:
LenaWriter [7]4 years ago
4 0

The text itself determined how to solve the problem.

Namely, two object are given in two relations and we conclude that we have two variables that we present with two equations.

We will take hardcover books as x and paperbacks as y.

First equation is  4x+10y=64

Second equation is  5x+7y=58

This is system of two linear equations with two variables

To solve this system we will use Gaussian agorithm with which we make

gradual elimination of the variables.

We will multiply first equation with number 4 and second with number (-5)

and get

20x+50y=320   and   -20x-28y=-232

When we add first equation to another we get

variable x is eliminated  

50y-28y=320-232 => 22y=88 => y=88/22=4

y=4  when we replace variable y in the first equation before multiplying

we get  4x+10*4=64 => 4x+40=64 => 4x=64-40 => 4x=24 => x=24/4=6

x=6

Total charge for hardcovers is  => 4x+5x=9x=9*6=54$

Total charge for paperbacks is => 10y+7y=17y=17*4=68$

Good luck!!!



olchik [2.2K]4 years ago
4 0

Answer:

The text itself determined how to solve the problem.

Namely, two object are given in two relations and we conclude that we have two variables that we present with two equations.

We will take hardcover books as x and paperbacks as y.

First equation is  4x+10y=64

Second equation is  5x+7y=58

This is system of two linear equations with two variables

To solve this system we will use Gaussian agorithm with which we make

gradual elimination of the variables.

We will multiply first equation with number 4 and second with number (-5)

and get

20x+50y=320   and   -20x-28y=-232

When we add first equation to another we get

variable x is eliminated  

50y-28y=320-232 => 22y=88 => y=88/22=4

y=4  when we replace variable y in the first equation before multiplying

we get  4x+10*4=64 => 4x+40=64 => 4x=64-40 => 4x=24 => x=24/4=6

x=6

Total charge for hardcovers is  => 4x+5x=9x=9*6=54$

Total charge for paperbacks is => 10y+7y=17y=17*4=68$

Good luck!!!

Step-by-step explanation:

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A walker has travelled 9 km along a trail. If he has completed 80% of the trail, how much further does he still have to go?
Anit [1.1K]

Answer:

2.25 km to go

Step-by-step explanation:

In order to get this answer, you have to figure out how many km 10% is, 0.1125. Then multiply that by the remaining 20% because he already finished 80% of the trail. So, 0.1125 x 20 = 2.25.

Hope this helps! :)

3 0
3 years ago
Please help!!!!!!
12345 [234]
The area of a circle is:

A=pr^2

You are told r=32 so

A=p32^2

A=1024p u^2
8 0
4 years ago
Read 2 more answers
If multiplying by 1/4 makes a positive number smaller then what does dividing by 1/4 do to the value of the number? Explain your
Free_Kalibri [48]

Hello,

If multiplying by 1/4 makes a positive number smaller then dividing  by 1/4 makes the number its being dividing to see how many times 1/4 can be put into that number. For Example,

2 / 1/4 = 8

1/4 can go into 2 eight times!

Hope This Helps!

5 0
3 years ago
A group of 8 friends went to lunch and spent a total of $76, which included the food bill and a tip of $16. They decided to spli
Rudik [331]

Answer:

1) The equation 1/8(x+16)=76/8 represents the situation, where x is the food bill.

2) The solution x=60 represents the total food bill.

These both answers are correct.

Step-by-step explanation:

Since there are 8 group of friends, and the total amount spent by them is $76 including the tip i.e $16.

If x is the food bill our equation can be:

(x+16)/8 = 76/8

Solving the equation

(x+16)/8 = 9.5

x+16= 9.5*8

x= 76 -16

x= 60

The food bill is x=60.

6 0
3 years ago
Read 2 more answers
30 POINTS I WILL GIVE U BRAINLIEST AND THANKS AND 5 STARS please help this is very important this is a big part of my grade
mars1129 [50]

Answer:

1.\:2^x=64, x=\boxed{6},\\2.\:x=\left(\frac{2}{3}\right)^3,x=\boxed{\frac{8}{125}}\\3.\:3\cdot (3^4)=3^x, x=\boxed{5}\\4.\:\frac{16}{25}=x^2,x=\boxed{\frac{4}{5}},

Step-by-step explanation:

1.\\\\2^x=64,\\\log 2^x=\log64,\\x\log 2=\log 64,\\x=\frac{\log 64}{\log 2}=\boxed{6}

2.\\x=\left(\frac{2}{5}\right)^3=\frac{2^3}{5^3}=\boxed{\frac{8}{125}}

3. This problem incorporates an exponent property.

Exponent property used: a^b\cdot a^c=a^{(b+c)}, yielding an answer of \boxed{5}

4.\\\\\frac{16}{25}=x^2,\\x=\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\boxed{\frac{4}{5}}

3 0
3 years ago
Read 2 more answers
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