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Iteru [2.4K]
3 years ago
9

Darla spent $120.37 on groceries in January, $108.45 in February, and $114.86 in March. What was the average monthly cost of Dar

la’s groceries?
Mathematics
2 answers:
alexandr402 [8]3 years ago
7 0
Average: (120.37 + 108.45 + 114.86)/3 = 114.56
lubasha [3.4K]3 years ago
4 0
Ok to find the average you need to add all three numbers.
120.37+108.45+114.86 =343.68
Then divide by the number of months
343.68/3 =114.56
So the average is $114.56
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determine if the sequence is geometric if it is find the common ratio the 8th term and the explicit formula can someone check my
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You can check the answer by yourself after seeing the below answer.

Step-by-step explanation:

A sequence is geometric only if has common ratio i.e. r=\frac{a2}{a1} =\frac{a3}{a2} whiere a1,a2 and a3 are first,second and third term of the sequence respectively.

1) Common ratio r=\frac{-18}{-3}=\frac{-108}{-18}=6\\

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Now using the above formula, we can find 8^{th} term=-3*(6)^{8-1} =-3*6^{7}=-839808.

2) Here

\frac{a2}{a1}\neq \frac{a3}{a2}\\\frac{-2}{-4}\neq \frac{1}{-2}\\\frac{1}{2}\neq\frac{1}{-2} so this is not geometric sequence so no need to proceed further.

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Now using the above formula, we can find 8^{th} term=-3*(-5)^{8-1} =-3*(-5)^{7}=234375.

4) Common ratio r=\frac{-6}{1}=\frac{36}{-6}=-6\\

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Now using the above formula, we can find 8^{th} term=1*(-6)^{8-1} =1*(-6)^{7}=-279936.

5)Common ratio r=\frac{-8}{4}=\frac{16}{-8}=-2\\

 Explicit formula a_{n} =a_{1} .(-2)^{n-1}

Now using the above formula, we can find 8^{th} term=4*(-2)^{8-1} =4*(-2)^{7}=-512.

6)Common ratio r=\frac{-8}{-2}=\frac{-32}{-8}=4\\

 Explicit formula a_{n} =a_{1} .(4)^{n-1}

Now using the above formula, we can find 8^{th} term=-2*(4)^{8-1} =-2*(4)^{7}=-32768.






3 0
3 years ago
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