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Ksju [112]
3 years ago
15

Mike is buying a box of juice pouches. Flav-O-Squeeze costs $5.88 for 12 pouches. Turbo Taste costs $10.20 for 20 pouches. How m

uch more does Turbo Taste cost per pouch?
Mathematics
1 answer:
Kruka [31]3 years ago
7 0

Answer:

2 cents

Step-by-step explanation:

you would just divide the Flav-O-Squeeze price by 12 since there are 12 pouches and the Turbo Taste price by 20 since there are 20 pouches and then you would get 1 pack of Flav-O-Squeeze is 49 cents and 1 pack of Turbo Taste is 51 cents and if you subtract them Turbo Taste is 2 cents more then Flav-O-Squeeze

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Step-by-step explanation:

To solve this question, we need to understand the Poisson and the binomial probability distributions.

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x is the number of sucesses

e = 2.71828 is the Euler number

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Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

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C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Poisson distribution with a mean of 0.08 flaws per square foot of plastic panel. Assume an automobile interior contains 10 square feet of plastic panel.

So \mu = 10*0.08 = 0.8

(a) What is the probability that there are no surface flaws in an auto's interior?

Single car, so Poisson distribution. This is P(X = 0).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.8}*(0.8)^{0}}{(0)!} = 0.4493

44.93% probability that there are no surface flaws in an auto's interior

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws?

For each car, there is a p = 0.4493 probability of having no surface flaws. 10 cars, so n = 10. This is P(X = 10), binomial, since there are multiple cars and each of them has the same probability of not having a surface defect.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.4493)^{10}.(0.5507)^{0} = 0.0003

0.03% probability that none of the 10 cars has any surface flaws

(c) If 10 cars are sold to a rental company, what is the probability that at most 1 car has any surface flaws?

At least 9 cars without surface flaws. So

P(X \geq 9) = P(X = 9) + P(X = 10)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.4493)^{9}.(0.5507)^{1} = 0.0041

P(X = 10) = C_{10,10}.(0.4493)^{10}.(0.5507)^{0} = 0.0003

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.0041 + 0.0003 = 0.0044

0.44% probability that at most 1 car has any surface flaws

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