The <em>correct answer</em> is:
Place the point of the compass on the vertex of our original angle. Open the compass to a random width and draw an arc through both legs of the angle. Mark the points of intersection with this arc and the sides of the angle.
Explanation:
In order to copy the angle, we need to have some reference for how wide the angle is.
So far all we have is a ray. To get the reference for the width that we need, we will construct an arc in the original angle such that it intersects each side of the angle.
We will then set the compass width to these points of intersection. This will be how we set the width of the new angle.
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Answer:
I believe it's 4,080
Step-by-step explanation:
you just add the two numbers
Answer:
We need to find the value of b to make 8b - 27 be equal to 5, so:
8b - 27 = 5
We solve the equation:
8b = 5 + 27
8b = 32
We divide both sides by 8:
b = 32/8 = 4
So now, we know that b=4, and we can verify:
8*4 - 27 = 5
32 - 27 = 5 TRUE
