Answer: option d. the argument is valid by the law of detachment.
The law of detachment consists in make a conlcusion in this way:
Premise 1) a => b
Premise 2) a is true
Conclusion: Then, b is true
Note: the order of the premises 1 and 2 does not modifiy the argument.
IN this case:
Premise 1) angle > 90 => obtuse
Premise 2) angle = 102 [i.e. it is true that angle > 90]]
Conclusion: it is true that angle is obtuse
Answer:
C=10
Step-by-step explanation:
To solve this problem, first, you have to isolate it on one side of the equation. Remember, isolate c on one side of the equation.
3/2c+23-23=38-23 (subtract 23 from both sides.)
38-23 (solve.)
38-23=15
3/2c=15
2*3/2c=15*2 (multiply 2 from both sides.)
15*2 (solve.)
15*2=30
3c=30
3c/3=30/3 (divide by 3 from both sides.)
30/3 (solve.)
30/3=10
c=10
Basically you find the data points and fill in the values. For Point J it is (2,4). They want you to do this: (2-4,4-6)...it then becomes (-2,-2).
So
J: (-2,-2)
K: (-1, -4)
I: (-2, -5)
Those are your new points. I hope this helps love! :)
Slope= 3/2
CORRECT IF WRONG!!
Because of the fact that the amberjack is essentially three snappers, it can be shown as 3s
since one snapper is one s, and the amberjack is 3s, we can combine like terms
s+3s = 4s
because altogether, the fish weigh 44 pounds, 4s would equal 44 (shown as 4s = 44), from there, simply divide by 4 on both sides to get the weight of a snapper;
s = 11
Small bonus (finding an amberjack)
Since an amberjack is equal to three snappers, and a snapper is 11 pounds, an amberjack would be 33 pounds.
