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3 years ago

Help me A S A P. PLZZ

Mathematics

1 answer:

Sonbull [250]3 years ago

4 0

12.56 + (4*6)

12.56+24

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Is there a picture? I can't answer without knowing what you're asking

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Write a function equation that represents a line that contains the two points (-3, 5) and (2, 10).

Eva8 [605]

Step-by-step explanation:

1. 1st of all calculate the gradient

( - 3, 5) ( 2, 10)

Gradient = (10 - 5) / ( 2--3)

= 1

2. Then find the eq

Y = mx + c

Where m is the gradient

y= 1x + c

Now replace any 2 coordinates from above in the eq.

For ex I'm taking (2, 10)

Y = 1x + c

In the coordinate, x = 2 and y =10

By replacing this in the eq, I will find c

10 = 1(2) + c

2 + c = 10

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3 years ago

ASAP HELP WILL GIVE BRAINLY

timurjin [86]

Answer:

$7x - 4y = -4\\(7x - 7x) - 4y = -7x - 4\\-4y = -7x - 4\\\frac{-4}{-4}y = \frac{-7x - 4}{-4}\\y = \frac{7}{4}x + 1\\m = \frac{7}{4}\\b = 1$

m = slope

b = y-intercept

Step-by-step explanation:

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3 years ago

A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of t

Tomtit [17]

Answer:

$0.54\,\,m^3$

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m × $\frac{1.2}{2}=0.6\,\,m$ (as height of small locker is half the height of big locker )

To find: total volume of one big locker and one small locker

Solution:

Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= $0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6$

$=0.5\times 0.6\left ( 1.2+0.6 \right )\\=0.3(1.8)\\=0.54\,\,m^3$

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3 years ago

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What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (2,

vekshin1

Answer:

all work is shown and pictured

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3 years ago

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