Answer:
.................. ........
Answer:
x=4
Step-by-step explanation:
if you do ![\sqrt[3]{64}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D)
you'll get that 
is 64.
Ok so if -6 is the y intercept you look for -6 on the y axis and use rise over run up one over one until you can't plot anymore and then down one over one and do the same thing did that help you Phil?
I think it is number 2, x^2-x+2
Answer:
f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.
Step-by-step explanation:
The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.
* if x>1, then x-1>0.
* Also since the parabola opens up, then y>5.
So let's solve y=(x-1)^2+5 for x.
Subtract 5 on both sides:
y-5=(x-1)^2
Take square root of both sides:
Plus/minus sqrt(y-5)=x-1
We want x-1>0:
Sqrt(y-5)=x-1
Add 1 on both sides:
Sqrt(y-5)+1=x
Swap x and y:
Sqrt(x-5)+1=y
x>5
y>1
