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garri49 [273]
2 years ago
12

Write a system of linear inequalities represented by the graph? Inequality 1: Inequality 2:

Mathematics
1 answer:
alina1380 [7]2 years ago
8 0

Answer:

y > x - 2

y >= 5x + 1

Step-by-step explanation:

You might be interested in
Hal is asked to write an exponential function to represent the value of a $10,000 investment decreasing at 2% annually. What mul
Inga [223]

Answer

The multiplicative rate of change that should be in Hal’s function = 49/50=0.98

                                                                                                                  =9.8×10⁻¹

Explanation

The investment of $10,000 decreases by 2% every year. So the following year is usually (100 - 2)=98% of the previous year. This is a geometric progression.

In this case the first term = 10000

The second term = 98% × 10000 = 9800.

The common ratio = 9800/10000=49/50

The multiplicative rate of change that should be in Hal’s function = 49/50=0.98.

The equation of the exponential rate would be;

10,000ₓ0.98ⁿ.

where n is the number years.

Hope his helps! ;)

8 0
2 years ago
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!! I CANNOT RETAKE THIS!!<br><br> Simplify.
NNADVOKAT [17]

Answer:  \frac{2x(5x + 1)}{4x - 1}

<u>Step-by-step explanation:</u>

\frac{4x^{3}-12x^{2}}{4x^{2}+7x - 2} ÷ \frac{2x^{2}-6x}{5x^{2}+11x + 2}

= \frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)} ÷ \frac{2x(x - 3)}{(5x + 1)(x + 2)}

= \frac{4x^{2}(x - 3)}{(4x - 1)(x + 2)} x \frac{(5x + 1)(x + 2)}{2x(x - 3)}

= \frac{2x(5x + 1)}{4x - 1}

8 0
3 years ago
I don't know what to do or how to do it ​
OleMash [197]

Answer:

i think you multiple the measure

3 0
3 years ago
Read 2 more answers
Please help me with this equation, add process too. Thanks
ICE Princess25 [194]

\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}

Let's solve ~ ☂

\qquad \sf  \dashrightarrow \:  - 0.6(m + 1) = 3

\qquad \sf  \dashrightarrow \:  - (m + 1) = 3 \div 0.6

\qquad \sf  \dashrightarrow \:  - (m + 1) = 5

\qquad \sf  \dashrightarrow \:  - m  -  1= 5

\qquad \sf  \dashrightarrow \:  - m = 5 + 1

\qquad \sf  \dashrightarrow \:  - m =  6

\qquad \sf  \dashrightarrow \: m =  - 6

I hope it helps ~

6 0
2 years ago
Find(f−g)(x) f(x)=x2−6xandg(x)=−2x+3 <br> A x2−4x+3 <br> B x2+4x−3 <br> C x2−4x−3 <br> D x2+4x+3
3241004551 [841]

Answer:

option C is the answer......

8 0
2 years ago
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