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3 years ago

5

Ax+z=aw-y solve for a

1 answer:

kodGreya [7K]3 years ago

8 0

I don’t think you wrote the problem correct, I’m a freshmen in college and your problem is stating A*X+Z=A*w-y to solve this problem we would need to know the givens. I may be completely spacing on this being the fact a tool a gap year before going back to school but this doesn’t seem right, sorry

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Help me pls i dont understand this

vazorg [7]

Step-by-step explanation:

Notice that:

15x = 5 * 3x and 10y = 5 * 2y.

Since there is a common factor of 5,

we can take out the factor.

=> 15x + 10y = (5)(3x) + (5)(2y) = 5(3x + 2y).

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2 years ago

The sum of the first three terms of geometric sequence is 14. If the first term is 2, find the possible values of the sum of the

Irina18 [472]

Geometric series are in the form of

$a +a*r +a*r^2+...$

Where a is the first term and r is the common ratio .

And it is given that

$2 +2*r +2*r^2=14$

$2r^2+2r-12=0$

$r^2 +r-6=0$

$(r+3)(r-2)=0$

r=-3,2

So the first five terms are

$2+2(-3)+2(-3)^2+2(-3)^3+2(-3)^4 or 2+2(2)+2(2)^2+2(2)^3+2(2)^4$

= 2-6+18-54+162 or 2+4+8+16+32

= 122 or 62

4 0

2 years ago

Read 2 more answers

Please HELP I WILL GIVE BRAINLIEST

Arada [10]

Answer:

1/3

Step-by-step explanation:

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2 years ago

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Which statements accurately describe the function f(x) = 3(StartRoot 18 EndRoot) Superscript x? Select three options. The domain

Studentka2010 [4]

Answer:

The domain is all real numbers.

The initial value is 3

The simplified base is $9\sqrt{2}$

Step-by-step explanation:

The given function is $f(x)=3(\sqrt{18})^x$ .

To find the initial value, we put x=0 into the function:

$f(0)=3(\sqrt{18})^0$ .

$f(0)=3(1)=3$ .

The initial value is actually 3.

The given function is an exponential function, therefore the domain is all real numbers.

The range of this function refers to all values of y for which the function is defined.

The line y=0, is the horizontal asymptote.

The range is $y\:>\:0$

The simplified base is $3\sqrt{18}=3\sqrt{9\times2}$ .

$3\sqrt{18}=3\sqrt{9}\times\sqrt{2}$

$3\sqrt{18}=3\times3\times\sqrt{2}$

$3\sqrt{18}=9\sqrt{2}$

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2 years ago

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Given: x - 6.3333 ≤ 1.5 .

Inessa05 [86]

Answer:

$x$ or $(-\infty, 47/6]$

Step-by-step explanation:

Note that $6.3333 = 6 1/3 = 19/3 = 38/6$ .

Also, note that $1.5 = 1 1/2 = 3/2 = 9/6$ .

So, the inequality is really equal to $x-38/6$ .

We can then add $38/6$ to both sides to get $x$ .

So, the solution is $x$ , or in interval notation, $(-\infty, 47/6]$

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2 years ago