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Answer:
30 celsius
Explanation:
30 celsius = 86 fahrenheit
Answer:
8.24 m/s
Explanation:
Given:
t = 2.10 s
v₀ᵧ = 0 m/s
vₓ = 22.2 cos(-68.2) m/s
aₓ = 0 m/s²
Find: v₀
In the x direction:
v = at + v₀
22.2 cos(-68.2) = (0) (2.10) + v₀ₓ
v₀ₓ = 8.24
v₀² = v₀ₓ² + v₀ᵧ²
v₀² = (8.24)² + (0)²
v₀ = 8.24 m/s
Thank you for posting your question here at brainly. I think your question is incomplete. Below is the complete question, it can be found elsewhere:
What is the probability of finding an electron within one Bohr radius of the nucleus?<span>Consider an electron within the 1s orbital of a hydrogen atom. The normalized probability of finding the electron within a sphere of a radius R centered at the nucleus is given by 1-a0^2[a0^2-e^(-2R/a0)(a0^2+2a0R+2R2)]. Where a0 is the Bohr radius (for a hydrogen atom, a0 = 0.529 Å.). What is the probability of finding an electron within one Bohr radius of the nucleus? What is the probability of finding an electron of the hydrogen atom within a 2.30a0 radius of the hydrogen nucleus?
Below is the answer:
</span><span>you plug the values for A0 and R into your formula</span>
Explanation:
Given that,
An ideal horizontal spring-mass system oscillates with a period of 0.60 seconds.
Mass is 3 kg but the spring constant is not known. We need to find the frequency of oscillations when this same spring and mass are arranged to hang vertically. We know that the relation between frequency and time period is inverse. Frequency is given by :
Hence, the correct option is (d) "none of the above".