Hello!!
For this, we only need frequency and speed, so for calculate we applicate formula:
Yes it does. But not always
Explanation:
W = PE
W = mgh
1500 J = (20 kg) (9.8 m/s²) h
h = 7.65 m
Round as needed.
Answer:
E1_max = 866 V/m...................................... option D
Explanation:
We know that for linearly polarized light, relation between intensity and electric field is given by:
I_avg = (1/2)*c*e0*E_max^2
I_avg = (1/2)*3*10^8*8.854*10^-12*1000^2
I_avg = 1328.1 W/m^2
Now given that light is already polarized, So Using Malus's law, Intensity of light after passing through polarizer will be:
I1 = I_avg*(cosФ )^2
Ф = 30 deg, So
I1 = 1328.1*(cos 30 deg)^2 = 996.1 W/m^2
Now electric field corresponding to above Intensity will be:
I1 = (1/2)*c*e0*E1_max^2
E1_max = sqrt (2*I1/(c*e0))
E1_max = sqrt (2*996.1/(3*10^8*8.854*10^-12))
E1_max = 866 V/m
