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3 years ago

In order for combustion to occur what needs to happen

2 answers:

5 0

Pretty much combustion is the reaction of oxygen to a compound that contains carbon and hydrogen. That's why it creates CO2 and H2O

larisa86 [58]3 years ago

5 0

<span>The ignition point for a given fuel is met.</span>

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Carbon dioxide is released into the atmosphere by _____.

loris [4]

It is released in the atmosphere by chemicals

3 0

3 years ago

Read 2 more answers

Moving from the element with atomic number 10 to atomic number 11 on the periodic table, there is a change in reactivity. In thr

bazaltina [42]

Answer:

Explanation:

Ne has its outside shell full of electrons; therefore, its reaction with other elements is minimal if at all. Na, the next element, has 1 more proton and 1 more electron. More importantly that added electron is in the outside shell. It can fill that shell by ADDing 7 more electrons or LOSing the one electron. Obviously, it loses the one electron and it does so with gusto which makes Na a very reaction element while Ne is not reactive at all. Now follow oobleck's instructions, add what you read to what I've written,then summarize all of it in your own words.

7 0

3 years ago

Which of the following statements is true for ideal gases, but is not always true for real gases?

xxMikexx [17]

Answer:

C. Replacing one gas by another under the same conditions, has no effect on pressure.

Explanation:

Ideal gas:

A gas is treated as an ideal gas if temperature is high and pressure is low.

Kinetic energy for ideal gas given as

$K.E.=\dfrac{3}{2}KT$

So when temperature of gas is increases then Average molecular kinetic energy will also increases.

The size of molecule is negligible as compare to the dimension of container. It mean that volume occupied by molecule is less as compare to the volume of container.

The between molecules is perfectly elastic.

Ideal gas equation

P V = m R T

So the option C is not always true.

4 0

3 years ago

A solid cylinder is mounted above the ground with its axis of rotation oriented horizontally. A rope is wound around the cylinde

Romashka [77]

Answer:

(a)10.5 rad/s2

(b) 20.9 rev

Explanation:

As the block of mass 53 kg is falling and pulling on the rope. The tension force on the rope must be equal to the gravity acting on the block according to Newton's 3rd law

T = mg = 53*9.81 = 519.93 N

Since this tension force would rotate the cylinder freely without any friction. The torque created by this tension force is

To = TR = 519.93 * 0.36 = 187.17 Nm

This solid cylinder would have a moment of inertia around it's rotating axis of:

$I = \frac{mR^2}{2} = \frac{275 * 0.36^2}{2} = 17.82kgm^2$

(a)We can use Newton's 2nd law to calculate the angular acceleration exerted by such torque on the solid cylinder

$\alpha = \frac{To}{I} = \frac{187.17}{17.82} = 10.5 rad/s^2$

(b) With such constant angular acceleration, the angle it would make after 5s is

$\theta = \frac{\alphat^2}{2} = \frac{10.5*5^2}{2} = 131.3 rad$

Since each revolution equals to $2\pi rad$ of angle, we can calculate the number of revolution it makes

$\frac{\theta}{2\pi} = \frac{131.3}{6.28} \approx 20.9 rev$

(c) Assume the thickness of the rope is negligible (and its wounded radius is unchanging), we can calculate the rope length unwinded after rotating 131.3rad

$\theta R = 131.3*0.36 = 47.27 m$