Answer:
The equation of line passing through points (1 , 3) and perpendicular to given line is  y =  x +
 x +  
 
Step-by-step explanation:
Given as :
The equation of line is 3 x + 2 y = 5
Or , 2 y = - 3 x + 5
Or , y =  x +
 x +  
 
Another line is passing through point (1 , 3) and perpendicular to given line equation
Now, <u>From standard line equation</u>
i.e y = m x + c
where m is the slope of the line and c is the y-intercept
Now, comparing the given line equation with standard line equation
i.e y =  x +
 x +  
 
So, The slope of line = m =  
According to question
Another line is perpendicular to the given line
So, for perpendicular property, The product of the lines = - 1
Let the sloe of another line = M
So, m × M = - 1
∴ M = 
Or. M = 
I.e M = 
So, the slope of another line = M = 
Now, equation of line passing through slope M and point (1 , 3)
I.e equation of line in slope-points
So, y -  = m ( x -
 = m ( x -  )
 )
or, y - 3 = (  ) × ( x - 1 )
) × ( x - 1 )
Or, 3 × (y - 3) = 2 × (x - 1) 
Or, 3 y - 9 = 2 x - 2
Or, 3 y = 2 x - 2 + 9
Or, 3 y = 2 x + 7
∴ y =  x +
 x +  
 
So, The equation = y =  x +
 x +  
 
Hence, The equation of line passing through points (1 , 3) and perpendicular to given line is  y =  x +
 x +  Answer
  Answer