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Butoxors [25]
3 years ago
7

Suppose we want to test the claim that the majority of adults are in favor of raising the vote age to 21. Is the hypothesis test

left tailed, right tailed or two tailed
Mathematics
1 answer:
Fofino [41]3 years ago
8 0

Answer:

The hypothesis test is right-tailed.

Step-by-step explanation:

We are given that we want to test the claim that the majority of adults are in favor of raising the voting age to 21.

Let p = <u><em>proportion of adults who are in favor of raising the voting age to 21</em></u>

So, Null Hypothesis, H_0 : p \leq 50%

Alternate Hypothesis, H_A : p > 50%

As we know that the majority is there when we have more 50% chance of happening of that event.

Here, the null hypothesis states that the proportion of adults who are in favor of raising the voting age to 21 is less or equal to 50%.

On the other hand, the alternate hypothesis states that the proportion of adults who are in favor of raising the voting age to 21 is more than 50%.

This shows that our hypothesis test is right-tailed because in the alternate hypothesis, the greater than sign is included.

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2 years ago
A cone has a radius of 10 cm and and height of 9 cm. What is the approximate volume of the cone? Use 3.14 for π.
astraxan [27]

Answer:

The volume of the cone is 942cm^3

Step-by-step explanation:

The given cone has a radius of 10 cm and and height of 9 cm.

The volume of a cone is given by:

V=\frac{\pi r^2h}{3}

We substitute r=10 and h=9 ,  \pi=3.14 to obtain:

V=\frac{3.14*10^2*9}{3}

Simplify exponents to get:

V=\frac{3.14*100*9}{3}

Simplify:

V=314*3\\V=942cm^3

Therefore the volume of the cone is 942cm^3

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What is -0.75 - (-2/3) +0.4 + (-3/4) =
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Step-by-step explanation:

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Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

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Answer:

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