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hammer [34]
3 years ago
15

(5+2 i)(4-3i) - (5-2yi)(4-3i) in a + bi form, where y is a real number.

Mathematics
1 answer:
ElenaW [278]3 years ago
5 0
<span>(5+2 i)(4-3i) - (5-2yi)(4-3i)

Factorize out (4 -3i)

(4 -3i)( (5 +2i) - (5 -2yi) )

=  </span><span><span>(4 -3i)(5 +2i - 5 + 2yi)</span>

=  </span><span><span>(4 -3i)(5 - 5 + 2i + 2yi)</span>

= (4 -3i)(2i + 2yi)

= (4 - 3i)(2 + 2y)i.    Let's multiply the first two.
</span>
(4 - 3i)(2 + 2y) = 2*(4 -3i) + 2y*(4 - 3i)           
                      =  8 - 6i + 8y - 6yi
                      =  8 + 8y - 6i - 6yi

(4 - 3i)(2 + 2y)i = (8 + 8y - 6i - 6yi)i                Note: i² = -1
                       =  8i  + 8yi - 6i² - 6yi²
                       =  8i  +  8yi - 6(-1) - 6y(-1)  
                       =  8i  +  8yi  + 6 + 6y
                       =  6 + 6y + 8i + 8yi
                       =  (6 + 6y) + (8 + 8y)i    In the form a + bi
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1/2 x 2/4 x 3/6 x 4/8 x 5/10 x 6/12 simplified
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adelina 88 [10]
(-1, 2)

So the original point is (3, 4), when you move to the left or right, it changes the x value. When moving it to the right, you add the amount. When moving to the left, you subtract the amount

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After subtracting 2, you should be at (-1, 2)
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3 years ago
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lapo4ka [179]
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now we sub and find b, the y int
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so ur perpendicular equation is : y = -2x + 1
6 0
3 years ago
Read 2 more answers
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harkovskaia [24]

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if this is wrong im sorry. Hope i helped!

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