Answer:
Explanation:
Length of bar = L
mass of bar = M
mass of each ball = m
Moment of inertia of the bar about its centre perpendicular to its plane is
Moment of inertia of the two small balls about the centre of the bar perpendicular to its plane is
Total moment of inertia of the system about the centre of the bar perpendicular to its plane is
I = I1 + I2
Speed=
Distance=
speed= distance/time
So,
<u>Time</u><u>=</u><u> </u><u>distance</u><u>/</u><u>speed</u>
Time= 163/33
<h2>=</h2>
Answer:
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What is the work done in stretching a spring by a distance of 0.5m if the restoring force is 48N is 12 J.
Hooke's Law states that the more you deform a spring, the more force it will take to deform it further.
Notations: F= Restoring force
k= spring constant
x = spring displacement
Given: F = 48N,
x= 0.5m
By using Formula; F= kx
F = 48 = kx, k = F/x
k = 48/0.5 = 96 N/m
work done by spring = 1/2 (kx)² = 1/2(96x0.5)² = 12 J
work done by spring is 12J.
Learn more about the Hooke's law with the help of the following link:
brainly.com/question/2449067
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Unless the second ball's speed is twice the amount of the first ball's no they will not cross paths