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3 years ago

6

In a step-down transformer, which describes the primary winding compared with the secondary winding? A higher voltage and fewer

coils of wire B higher voltage and more coils of wire C lower voltage and fewer coils of wire D lower voltage and more coils of wire

2 answers:

kirill115 [55]3 years ago

7 0

B. Higher voltage and more coils of wire :)

kicyunya [14]3 years ago

5 0

B. higher voltage and more coils of wire

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Whenever you work a physics problem you should get into the habit of thinking about whether the answer is physicallyrealistic. T

nata0808 [166]

Answer:

a. No, typical small pickup truck springs are not large enough to compress 0.61{\rm m}.

Explanation:

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3 years ago

a child is swinging on swing, describe what happens to both the kinectic energy and potential enegry of the child as she swings

Igoryamba

Answer:

The K.E is maximum when the child is at the vertical position and the P.E is maximum at the extreme deviated position from the vertical.

Explanation:

A child is swinging on swing up and down has both kinetic and potential energy.
The total mechanical energy of the system is conserved throughout the system. At any instant the total mechanical energy is given by,

E = K.E + P.E

The K.E is maximum when the child is at the vertical position.
The P.E is maximum at the extreme deviated position from the vertical.
And when K.E is maximum P.E becomes minimum and vice versa as per the law of conservation of energy.

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3 years ago

A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the

alex41 [277]

Answer:

(a) $v_1 = a_1t_1 = 1.76 t_1$

(b) It won't hit

(c) 110 m

Explanation:

(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1

$v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1$

(b) The velocity of the car before the driver begins braking is

$v_1 = 1.76*20 = 35.2m/s$

The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

$a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2$

We can use the following equation of motion to calculate how far the car has travel since braking to stop

$s_2 = v_1t_2 + a_2t_2^2/2$

$s_2 = 35.2*5 - 7.04*5^2/2 = 88 m$

Also the distance from start to where the driver starts braking is

$s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352$

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

(c) The distance from the limb to where the car stops is 550 - 440 = 110 m

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3 years ago

How do the densities of the jovian and terrestrial planets compare?

timofeeve [1]

Hello

The jovian density is $1.33~g/cm^3$ , while the density of terrestrial planets is much higher. For instance, the earth's density is $5.51~g/cm^3$ . The reason of this difference is in the different chemical composition: while jupiter is made of gas (mainly hydrogen), with lower density, while the terrestrial planets are made of solid and liquid, with compounds of higher density.

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3 years ago

The KE of a body becomes 2 times of its original value then the new momentum will be more than its initial momentum by

sladkih [1.3K]

Answer:

√2

Explanation:

If the final kinetic energy is 2 times the initial kinetic energy:

KE = 2 KE₀

½ mv² = 2 (½ mv₀²)

v² = 2 v₀²

v = √2 v₀

Therefore, the ratio of the final momentum to the initial momentum is:

p / p₀

mv / (mv₀)

v / v₀

√2

7 0

3 years ago