Answer:
The airfoil shape and wing size will both affect the amount of lift. The ratio of the wing span to the wing area also affects the amount of lift generated by a wing. ... The lift then depends on the velocity of the air and how the object is inclined to the flow. Air: Lift depends on the mass of the flow.
Please give brainliest!!!
Answer:
The work done by the campers is 
(b) is correct option.
Explanation:
Given that,
Weight = 5000 N
Frictional force = 300 n
Distance = 1000 m
Constant rate of speed = 0.20 m/s²
We need to calculate the force
Using newton's law of motion




We need to calculate the work done
Using formula of work done

Put the value into the formula


Hence, The work done by the campers is 
The correct answer D: all of the above
Molecular formulas:
- CH₂O;
- C₂H₄O₂;
- C₆H₁₂O₆.
<h3>Explanation</h3>
The empirical formula of a compound tells only the ratio between atoms of each element. The empirical formula CH₂O indicates that in this compound,
- for each C atom, there are
- two H atoms, and
- one O atom.
The molecular weight (molar mass) of the molecule depends on how many such sets of atoms in each molecule. The empirical formula doesn't tell anything about that number.
It's possible to <em>add</em> more of those sets of atoms to a molecular formula to increase its molar mass. For every extra set of those atoms added, the molar mass increase by the mass of that set of atoms. The mass of one mole of C atoms, two mole of H atoms, and one mole of O atoms is
.
- CH₂O- 30.0 g/mol;
- C₂H₄O₂- 30.0 + 30.0 = 2 × 30.0 = 60.0 g/mol;
- C₃H₆O₃- 30.0 + 30.0 + 30.0 = 3 × 30.0 = 90.0 g/mol.
It takes one set of those atoms to achieve a molar mass of 30.0 g/mol. Hence the molecular formula CH₂O.
It takes two sets of those atoms to achieve a molar mass of 60.0 g/mol. Hence the molecular formula C₂H₄O₂.
It takes
sets of those atoms to achieve a molar mass of 180.0 g/mol. Hence the molecular formula C₆H₁₂O₆.