Answer:
P = 4000 [Pa]
Explanation:
Pressure is defined as the relationship between Force and the area where the body rests.
The support area is equal to:
![A=50*20=1000[cm^{2} ]](https://tex.z-dn.net/?f=A%3D50%2A20%3D1000%5Bcm%5E%7B2%7D%20%5D)
But we must convert from square centimeters to square meters.
![1000[cm^{2}]*\frac{1^{2}m^{2} }{100^{2}m^{2} }=0.1[m^{2} ]](https://tex.z-dn.net/?f=1000%5Bcm%5E%7B2%7D%5D%2A%5Cfrac%7B1%5E%7B2%7Dm%5E%7B2%7D%20%20%7D%7B100%5E%7B2%7Dm%5E%7B2%7D%20%20%7D%3D0.1%5Bm%5E%7B2%7D%20%5D)
And the pressure is:
![P=\frac{F}{A} \\P=400/0.1\\P=4000[N/m^{2} ]or 4000[Pa]](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BF%7D%7BA%7D%20%5C%5CP%3D400%2F0.1%5C%5CP%3D4000%5BN%2Fm%5E%7B2%7D%20%5Dor%204000%5BPa%5D)
Explanation:
there is no relationship between small mass and the bigger mass, but it can be related with the acceleration. Since Force is constant, acceleration is inversely proportional to the mass. Greater the mass, lesser is the acceleration and vise versa
work is done by the pulling force which is same as the tension force in the rope. the net work done is zero for the crate since crate moves at constant velocity. but there is work done by the tension force which is equal in magnitude to the work done by the frictional force.
T = tension force in the rope = 115 N
d = displacement of the crate = 7.0 m
θ = angle between the direction of tension force and displacement = 37 deg
work done on the crate is given as
W = F d Cosθ
inserting the values given above
W = (115) (7.0) Cos37
W = 643 J
Multiply 6 x 60 to get the frequency.
Answer:
Acceleration
Explanation:
The advertisement is describing the acceleration of the car.
Acceleration is the rate of change of velocity per unit of time. It can be expressed mathematically as;
Acceleration =
v is the final velocity
u is the initial velocity
t is the time taken
Any quantity that specifies the rate of change of velocity of a body within a given time frame is describing its acceleration.