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3 years ago

How to write a whole number as a improper fraction

1 answer:

4 0

Follow these 3 steps to convert a mixed number to an improper fraction:<span>Multiply the whole number by the denominator.Add the answer from Step 1 to the numerator.<span>Write answer from Step 2 over the denominator.</span></span>

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F(x) = 6x-6, g(x) = -x^2 find (f*g)(x)

Andre45 [30]

Answer:

y=6x−6;gx=−x2

Step-by-step explanation:

y=6x−6;gx=−x2

5 0

2 years ago

What is the value of ine^4?

Gnoma [55]

Answer:

The value of ln e^4 is 4 so the answer is D 4 P.S i know its right i just took the test

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The measure of XYZ is 45. The length of radius YZ is 6 inches. What is the area of sector XYZ?

balandron [24]

Answer:

area of a sector = 14.13 yards²

Step-by-step explanation:

XYZ is a sector of a circle. The radius YZ is 6 inches .The angle of the sector is given as 45°. The area of the sector can be solved as follows.

area of a sector = ∅/360 × πr²

where

r = radius

∅ = center angle

r = 6 inches

∅ = 45°

area of a sector = 45/360 × 3.14 × 6²

area of a sector = 45/360 × 3.14 × 36

area of a sector = 45/360 × 113.04

area of sector = 1/8 × 113.04

area of a sector = 14.13 yards²

6 0

3 years ago

Read 2 more answers

Sue gets paid 215 dollars every 2 month how much will she have in a year all together

professor190 [17]

In a year she will have 1290$ because if she gets paid every 2 months and there are 12 months, 12/2 equals 6 times she gets paid a year. So 215 times 6 is 1290

4 0

3 years ago

Read 2 more answers

5-4. Solve each of the following equations for the indicated variable. Use your Equation Mat if it is helpful. Write down each o

balu736 [363]

QUESTION 1

The given equation is :

$2(y - 3) = 4$
We want to solve for y. This means we have to isolate y on one side of the equation while all other constants are also on the other side of the equation,

We first divide both sides by 2 to obtain,

$\frac{2(y - 3)}{2} = \frac{4}{2}$

We cancel out the common factors to get,

$y - 3 = 2$

We now group like terms to get,

$y = 3 + 2$

We simplify to obtain,

$y = 5$

QUESTION 2

The given equation is

$2x + 5y = 10$
We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

This implies that,

$2x= 10 - 5y$

We now divide through by 2, to obtain,

$\frac{2x}{2} = \frac{10}{2} - \frac{5y}{2}$

This will now give us,

$x = 5 - \frac{5}{2} y$

QUESTION 3

The given equation is
$6x + 3y = 4y + 11$

We want to solve for y. This means that we need to isolate y on one side of the equation, while all other variables and constants are also on the other side of the equation.

We first of all group all the y terms on one side of the equation to obtain,

$6x - 11 = 4y - 3y$

We simplify to get,

$6x - 11 = y$

This implies that,

$y = 6x - 11$

QUESTION 4

The given equation is,

$3(2x + 4) = 2 + 6x + 10$

We want to solve for x. This means that we need to isolate x on one side of the equation, while all other variables and constant are also on the other side of the equation.

Let us first expand the brackets to get,

$6x + 12 = 2 + 6x + 10$
This implies that

$6x + 12 = 6x + 12$

We group like terms to get,

$6x - 6x = 12 - 12$

We now simplify both sides to get,

$0x = 0$

We don't want x to vanish, so let us try to divide both sides by zero to get,

$x = \frac{0}{0}$

This is an indeterminate form, which implies that, x has infinitely many solutions. This means that all the real numbers are solution to the equation.

$\therefore \: x \in \: R$

QUESTION 5

The given equation is,

$y = - 3x + 6$

We want to solve for x, so we add the additive inverse of 6, which is -6 to both sides of the equation to get,

$y - 6 = - 3x$

We rewrite this to obtain,

$- 3x = y - 6$

We divide through by -3 to get,

$\frac{ - 3x}{ - 3} = \frac{y}{ - 3} - \frac{6}{ - 3}$

This will give us,

$x = - \frac{y}{3} + 2$

or

$x= 2 - \frac{1}{3} y$

5 0

3 years ago