Sum/difference:
Let

This means that

Now, assume that
is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that
was rational, which proves that the sum/difference of the two given terms was irrational
Multiplication/division:
The logic is actually the same: if we multiply the two terms we get

if again we assume x to be rational, we have

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.
Just borrow from the 7 and take the 1 to the 2 and that will make it as 12 so then you subtract 12 - 4 and the answer will be 1,180
A)
SLOPE OF f(x)
To find the slope of f(x) we pick two points on the function and use the slope formula. Each point can be written (x, f(x) ) so we are given three points in the table. These are: (-1, -3) , (0,0) and (1,3). We can also refer to the points as (x,y). We call one of the points

and another

. It doesn't matter which two points we use, we will always get the same slope. I suggest we use (0,0) as one of the points since zeros are easy to work with.
Let's pick as follows:


The slope formula is:
We now substitute the values we got from the points to obtain.

The slope of f(x) = 3
SLOPE OF g(x)
The equation of a line is y=mx+b where m is the slope and b is the y intercept. Since g(x) is given in this form, the number in front of the x is the slope and the number by itself is the y-intercept.
That is, since g(x)=7x+2 the slope is 7 and the y-intercept is 2.
The slope of g(x) = 2
B)
Y-INTERCEPT OF g(x)
From the work in part a we know the y-intercept of g(x) is 2.
Y-INTERCEPT OF f(x)
The y-intercept is the y-coordinate of the point where the line crosses the y-axis. This point will always have an x-coordinate of 0 which is why we need only identify the y-coordinate. Since you are given the point (0,0) which has an x-coordinate of 0 this must be the point where the line crosses the y-axis. Since the point also has a y-coordinate of 0, it's y-intercept is 0
So the function g(x) has the greater y-intercept
X + 4x = 40
5x = 40
5x/5 = 40/5
x = 8
1x 8 = 8
4x 8 = 32
Check=
8 + 32 = 40
The numbers are 8 and 32
Answer:
Option (3)
Step-by-step explanation:
By applying cosine rule in the triangle ABC,
BC² = AC² + AB² - 2(AC)(AB)cosA
5² = 3² + 7²- 2(3)(7)cosA
25 = 9 + 49 - 42cos(A)
25 = 58 - 42cos(A)
cos(A) = 
A = 
A = 38.21°
A ≈ 38°
Option (3) will be the correct option.